Answer:
Monica is not correct.
Step-by-step explanation:
First of all, if 4 bottles only cost $4, then how would only 2 cost more? (She said the two bottles would be $25, which doesn’t make sense.)
The answers to each of the given problems are;
1) Sum of two smallest integers = 23
2) 3x + 6
3) 7.5 m/s²
<h3>How to find the sum of consecutive Integers?</h3>
1) We are told that sum of 4 consecutive integers is increased by 20 and equals 70. Thus, we have;
x + (x + 1) + (x + 2) + (x + 3) + 20 = 70
4x + 26 = 70
4x = 70 - 26
4x = 44
x = 44/4
x = 11
Thus, sum of two smallest integers = 11 + 11 + 1 = 23
2) Let the consecutive odd numbers be;
x, (x + 2) and (x + 4)
Sum of these consecutive odd numbers is;
x + x + 2 + x + 4 = 3x + 6
3) We are given the equation to find the acceleration as;
(v_final)² - (v_initial)² = 2ad
We are given;
v_final = 40 m/s
v_initial = 10 m/s
d = 100 m
Thus;
40² - 10² = 2a(100)
1500 = 200a
a = 1500/200
a = 7.5 m/s²
Read more about sum of integers at; brainly.com/question/17695139
#SPJ1
Answer:
15v^5+4v^3-24v^2
Step-by-step explanation:
Distribute the Negative Sign:
=3v5+8v3−10v2+−1(−12v5+4v3+14v2)
=3v5+8v3+−10v2+−1(−12v5)+−1(4v3)+−1(14v2)
=3v5+8v3+−10v2+12v5+−4v3+−14v2
Combine Like Terms:
=3v5+8v3+−10v2+12v5+−4v3+−14v2
=(3v5+12v5)+(8v3+−4v3)+(−10v2+−14v2)
=15v5+4v3+−24v2
Answer:
=15v5+4v3−24v2
Hope this helps! :)
Answer:
The class width is 20
Step-by-step explanation:
In a frequency or a relative frequency distribution the class width is calculated as the difference between the lower or upper class limits of consecutive classes. A point to note is that all the categories or classes usually have the same class width.
We use the first two classes to calculate the class width by using their respective upper limits;
Class width = 89 - 69
Class width = 20
Answer:
3 :4
Step-by-step explanation:
Remember that odds are different than probability
favor : not in favor ( drawing something other than white)
9 white : 12 not white
Divide each by 3
9/3 : 12/3
3 :4
