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kari74 [83]
3 years ago
8

Find the slope p(1,-4) p(2,6)

Mathematics
1 answer:
Setler [38]3 years ago
5 0
M=10 just change the m into a p
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The height of a triangle is 2 less than 5 times its base. If the base of the triangle is x feet, and the area of the triangle is
Semmy [17]

Answer:

A. 5x^2 − 2x − 24 = 0

Step-by-step explanation:

height = 5b-2

b =x

We can rewrite the height as

h = 5x-2

We know the formula for area of a triangle

A = 1/2 bh

A =1/2 x * (5x-2)

Distributing the x

A=    1/2 (5x^2 - 2x)

We know A =12

12 = 1/2 (5x^2 - 2x)

Multiply each side by 2

12*2 = 2*1/2 (5x^2 - 2x)

24 = 5x^2 - 2x

Subtract 24 from each side

24-24 = 5x^2 - 2x-24

0 = 5x^2 - 2x-24


6 0
3 years ago
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A bakery sells, on average, 100 special breads per day and collects with these sales, on average, R $ 300.00. It was found that
Vlad [161]

If the price is p and the quantity of bread sold is q = 400 - 100p, the average collection, in reais, depending on the price p, is given by R (p) = (400 - 100p). P

For this collection to be R $ 300.00, you must have:

(400 - 100p). p = 300 ⇔ 4p - p² = 3 ⇔ p² - 4p + 3 = 0 ⇔ p = 1 or p = 3

R $ 300.00

The current price is R $ 3.00, as R $ 300,000 / 100 = R $ 3

To maintain the collection, the price must be lowered to R $ 1.00 (R $ 0.50 <R $ 1.00 <R $ 1.50)

ANSWER: letter A

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3 years ago
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2 more!! Enjoy the points!
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I hope you’re having a wonderful day :)
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Joshep drove his grandmother’s house which is 252 miles away in 3.5 hours. If he continues at the same speed,approximately how l
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Answer:

72 hours

Step-by-step explanation:

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3 years ago
If $3000 is deposited in an account that pays 5% interest, what is the difference in the amount after 4 years between the amount
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\bf \qquad \textit{Simple Interest Earned Amount}\\\\&#10;A=P(1+rt)\qquad &#10;\begin{cases}&#10;A=\textit{accumulated amount}\\&#10;P=\textit{original amount deposited}\to& \$3000\\&#10;r=rate\to 5\%\to \frac{5}{100}\to &0.05\\&#10;t=years\to &4&#10;\end{cases}&#10;\\\\\\&#10;A=3000(1+0.05\cdot 4)\implies \boxed{A=3600}\\\\&#10;-------------------------------\\\\

\bf \qquad \textit{Compound Interest Earned Amount}&#10;\\\\&#10;A=P\left(1+\frac{r}{n}\right)^{nt}&#10;\quad &#10;\begin{cases}&#10;A=\textit{accumulated amount}\\&#10;P=\textit{original amount deposited}\to &\$3000\\&#10;r=rate\to 5\%\to \frac{5}{100}\to &0.05\\&#10;n=&#10;\begin{array}{llll}&#10;\textit{times it compounds per year}\\&#10;\textit{annually, thus once}&#10;\end{array}\to &1\\&#10;t=years\to &4&#10;\end{cases}

\bf A=3000\left(1+\frac{0.05}{1}\right)^{1\cdot 4}\implies A=3000(1.05)^4\implies \boxed{A=3646.51875}\\\\&#10;-------------------------------\\\\&#10;\stackrel{\textit{compounded interest}}{3646.51875}~~-~~\stackrel{\textit{simple interest}}{3600}
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4 years ago
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