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nataly862011 [7]

3 years ago

14

Aaron bakes 3 trays of cookies each containing 10 cookies and Ethan bakes 4 trays of cookies each containing 12 cookies.

1 answer:

Sonbull [250]3 years ago

5 0

6((3 * 10) + (4 * 12)).....ur expression
6(30 + 48)
6(78)
468 cookies in 6 days

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Jim's father bought a new car 3 years ago for

Alexus [3.1K]

30% of 50,400 = 30240.

Therefore the percentage loss is 30% over the course of 3 years.

4 0

2 years ago

There was a bus that hit there was 2 married people and ten other passengers every single person died. how many people are alive

musickatia [10]

Answer:

2 people are are alive because all the single people(meaning they have no spouse) died do the married people are the only ones who survived.

Step-by-step explanation:

4 0

3 years ago

Lori creates the following design for a T-shirt.

kakasveta [241]

<u>Solution-</u>

From the figure,

AE = 2.4

EB = 2.8

BC = 11.7

Area of rectangle 1 = 8.68 sq.in

$\Rightarrow FH \times HI=8.68$

$\Rightarrow EB \times HI=8.68$ (∵ sides of the rectangle 2)

$\Rightarrow 2.8 \times HI=8.68$

$\Rightarrow HI=3.1$

Area of Triangle 1 = 6.48 sq.in

$\Rightarrow \frac{1}{2}\times AE \times EG= 6.48$

$\Rightarrow \frac{1}{2}\times AE \times (EF+FG)= 6.48$

$\Rightarrow \frac{1}{2}\times AE \times (EF+HI)= 6.48$ (∵ sides of the rectangle 1)

$\Rightarrow EF+3.1= 5.4$

$\Rightarrow EF=2.3$

$\Rightarrow BH=2.3$ (∵ sides of the rectangle 2)

$BC = BH+HI+IC$

$\Rightarrow 11.7= 2.3+3.1+IC$

$\Rightarrow IC=6.3$

The area of Rectangle 2,

$=EB\times BH =2.8\times 2.3=6.44\ sq.in$

The area of Triangle 2,

$\frac{1}{2}\times GI \times IC=\frac{1}{2}\times EB \times IC=\frac{1}{2}\times 2.8 \times 6.3=8.82\ sq.in$

The area of the whole figure = Area of Triangle 1 + Area of rectangle 1 + Area of Triangle 2 + Area of rectangle 2

= 6.48+8.68+8.82+6.44=30.42 sq.in

6 0

3 years ago

(4x²+9x-7)+6(x²-10x+3)

polet [3.4K]

Answer:

1Step-by-step explanation:

8 0

2 years ago

How many distinct diagonals of a convex heptagon (7-sided polygon) can be drawn?

valkas [14]

The convex heptagon has 14 distinct diagonals can be drawn

Step-by-step explanation:

A polygon is said to be a heptagon if it has 7 vertices, 7 sides and 7 angles. A heptagon is called a convex heptagon if the lines connecting any two non-adjacent vertices lie completely inside the heptagon

The formula of number of diagonals in any polygon is $d=\frac{n(n-3)}{2}$ , where

d is the number of the diagonals of the polygon
n is the number of sides of the polygon

∵ The heptagon has 7 sides

∴ n = 7

∵ The number of diagonals = $\frac{n(n-3)}{2}$

- Substitute n by 7 in the rule above

∴ The number of diagonals = $\frac{7(7-3)}{2}$

∴ The number of diagonals = $\frac{7(4)}{2}$

∴ The number of diagonals = $\frac{28}{2}$

∴ The number of diagonals = 14

The convex heptagon has 14 distinct diagonals can be drawn

Learn more:

You can learn more about the polygons in brainly.com/question/6281564

#LearnwithBrainly

4 0

3 years ago