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ziro4ka [17]
3 years ago
8

What is the domain of the graph ?

Mathematics
1 answer:
marysya [2.9K]3 years ago
3 0
The domain of the graph is all real numbers because the value doesn’t have an end point.
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30 points please help on these questions!
hichkok12 [17]

Answer:

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5 0
3 years ago
Which of the following is equivalent to f(x)?
Fynjy0 [20]

Answer:

  • D. x^{-3/2}

Step-by-step explanation:

<u>Given function:</u>

  • f(x) = \frac{1}{x\sqrt{x} }

<u>Equivalent expression is:</u>

  • \frac{1}{x\sqrt{x} } = x^{-1}x^{-1/2} = x^{-1 - 1/2} = x^{-3/2}

Correct choice is D

6 0
3 years ago
Need help solving for X
Inessa05 [86]
You can find the complementary angle for 28° first, which is 90°-28°=62°. Since this is a right triangle, you can then use trigonometry to find x (the hypotenuse). You have the angle and the adjacent side, so plug and play:

cos 62° = 350 / x
x = 350 / cos 62°
x = 745.5 ft
8 0
3 years ago
Read 2 more answers
Regular triangular pyramid has 6 cm long base edge and slant height k=9 cm. Find the lateral area of the pyramid.
gregori [183]

Answer:

81 cm²

Step-by-step explanation:

Since, the lateral face of a triangular pyramid is a triangle,

Given,

The base edge or the base of one lateral face of pyramid, a = 6 cm,

And, the slant height or the height of the face, k = 9 cm,

Thus, the area of one lateral face of the pyramid,

A=\frac{1}{2}\times a\times k

=\frac{1}{2}\times 6\times 9

=\frac{54}{2}

=27\text{ square cm}

We know that, a Regular triangular pyramid has 3 lateral faces,

Hence, the total lateral area of the pyramid,

L.A.=3\times\text{ The area of one lateral face}

=3\times 27

=81\text{ square cm}

5 0
3 years ago
Read 2 more answers
Please help me. 5(m-7)=-8(3m+8)
inessss [21]

Answer:

m = -1

Step-by-step explanation:

Solve for m:

5 (m - 7) = -8 (3 m + 8)

Hint: | Write the linear polynomial on the left hand side in standard form.

Expand out terms of the left hand side:

5 m - 35 = -8 (3 m + 8)

Hint: | Write the linear polynomial on the left hand side in standard form.

Expand out terms of the right hand side:

5 m - 35 = -24 m - 64

Hint: | Move terms with m to the left hand side.

Add 24 m to both sides:

24 m + 5 m - 35 = (24 m - 24 m) - 64

Hint: | Look for the difference of two identical terms.

24 m - 24 m = 0:

24 m + 5 m - 35 = -64

Hint: | Group like terms in 24 m + 5 m - 35.

Grouping like terms, 24 m + 5 m - 35 = (5 m + 24 m) - 35:

(5 m + 24 m) - 35 = -64

Hint: | Add like terms in 5 m + 24 m.

5 m + 24 m = 29 m:

29 m - 35 = -64

Hint: | Isolate terms with m to the left hand side.

Add 35 to both sides:

29 m + (35 - 35) = 35 - 64

Hint: | Look for the difference of two identical terms.

35 - 35 = 0:

29 m = 35 - 64

Hint: | Evaluate 35 - 64.

35 - 64 = -29:

29 m = -29

Hint: | Divide both sides by a constant to simplify the equation.

Divide both sides of 29 m = -29 by 29:

(29 m)/29 = (-29)/29

Hint: | Any nonzero number divided by itself is one.

29/29 = 1:

m = (-29)/29

Hint: | Reduce (-29)/29 to lowest terms. Start by finding the GCD of -29 and 29.

The gcd of -29 and 29 is 29, so (-29)/29 = (29 (-1))/(29×1) = 29/29×-1 = -1:

Answer: m = -1

7 0
3 years ago
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