A turning point occurs when the velocity is equal to zero, but the acceleration is not equal to zero.
t(x)=(x+5)^3+7
dt/dx=3(x+5)^2
d2t/dx2=6(x-5)
dt/dx=0 only when x=-5
However, since d2t/dx2(-5)=0, this point is an inflection point, not a turning point.
So there is no turning point for this function.
Now in this problem, it is even easier than the above to show that there is no turning point. A turning point by definition is when the derivative or velocity changes sign. Since in this case v=3(x+5)^2, for any value of x, v≥0, and thus never becomes negative, so it never changes from a positive to negative velocity because velocity in this instance is a squared function.
Answer:
The final balance is £1,720.
The total compound interest is £520
you don't even to round it at all
Answer:
Step 2 is wrong.
It should be 3x – <u>18</u> + 4x + 12 – 6x
Explanation:
3(x – 6) + (4x + 12) – 6x →
3x – 18 + 4x + 12 – 6x →
(3x + 4x – 6x) + (-18 + 12) →
x – 6
A = account
M = money
w = weeks
A = Mw
Hope this helps! Any questions let me know :)
