Answer:
12 white 28 printed
Step-by-step explanation:
x = white y = printed
x + y = 40————(1)
4.95x + 7.95y = 282————(2)
Solve for x using 1st equation
x = 40 - y Plug in for x using 2nd equation
4.95(40 - y) + 7.95y = 282 Solve for y
198 - 4.95y + 7.95y = 282
3y = 84
y = 28 Plug in for y using 1st equation
x + (28) = 40 Solve for x
x = 12
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9514 1404 393
Answer:
it is application of the multiplication property of equality
Step-by-step explanation:
You can use "cross products" to solve any proportion. What looks like a "cross product" is just application of the multiplication property of equality. That property says the variable value is unchanged if both sides of the equation are multiplied by the same value.
For your fraction, the "cross product" is what you get when you multiply both sides of the equation by 500.
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Note that the next step here is to divide by the x-coefficient, the 5 that was in the left-side denominator.
Please also note that this is exactly the same result you would get by multiplying the original equation by the original denominator of x.
In the question equation you have first the multiplication so the whole thing becomes equal to 15.
Now you just have to see what row of the given is equal to 15, too.
3х2^2 +3 = 3х4 + 3 = 12+3= 15
So, you see that the first is equal to the one in your question.
THIS IS THE COMPLETE QUESTION BELOW
The demand equation for a product is p=90000/400+3x where p is the price (in dollars) and x is the number of units (in thousands). Find the average price p on the interval 40 ≤ x ≤ 50.
Answer
$168.27
Step by step Explanation
Given p=90000/400+3x
With the limits of 40 to 50
Then we need the integral in the form below to find the average price
1/(g-d)∫ⁿₐf(x)dx
Where n= 40 and a= 50, then if we substitute p and the limits then we integrate
1/(50-40)∫⁵⁰₄₀(90000/400+3x)
1/10∫⁵⁰₄₀(90000/400+3x)
If we perform some factorization we have
90000/(10)(3)∫3dx/(400+3x)
3000[ln400+3x]₄₀⁵⁰
Then let substitute the upper and lower limits we have
3000[ln400+3(50)]-ln[400+3(40]
30000[ln550-ln520]
3000[6.3099×6.254]
3000[0.056]
=168.27
the average price p on the interval 40 ≤ x ≤ 50 is
=$168.27