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3 years ago

Lining up a wedding party for a photo.

Mathematics

1 answer:

gayaneshka [121]3 years ago

5 0

Answer:

Step-by-step explanation:

a) Number of arrangements in which bride is not next to the groom

= Total number of arrangements - Number of arrangements in which bride and groom are next to each other

= 10! - 2*9!

= 2903040

b) Number of arrangements such that groom is not at the leftmost position

= Total number of arrangements - Number of arrangements with groom at leftmost position

= 10! - 9!

= 3265920

c) Number of ways such that groom is not at one end

= Total number of arrangements - Number of arrangements with groom at one end

= 10! - 2*9!

= 2903040

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While working at the drugstore, Grace earns $9.83 per hours. How many hours will it take grace to earn $49.15?

RoseWind [281]

Answer:

Step-by-step explanation:

all you have to do is divide 49.15 by 9.83.

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3 years ago

The sum of -5, -9, and 10 is _______. A. 14 B. -14 C. 4 D. -4

saul85 [17]

Answer:

D. -4

Step-by-step explanation:

-5 + -9 = -14

-14 + 10 = -4

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3 years ago

Read 2 more answers

Estimate then record the product, 181×2

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I estimated it is around or near 360

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3 years ago

Sara got 720 marks out of 800 in the Basic Level Examination. How many percent of marks did she obtain?

RUDIKE [14]

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3 years ago

A total of 1 232 students have taken a course in Spanish, 879 have taken a course in French, and 114 have taken a course in Russ

ElenaW [278]

Answer:

$n(S\cap F \cap R)=7$

Step-by-step explanation:

The Universal Set, n(U)=2092

$n(S)=1232\\n(F)=879\\n(R)=114$

$n(S\cap R)=23\\n(S\cap F)=103\\n(F\cap R)=14$

Let the number who take all three subjects, $n(S\cap F \cap R)=x$

Note that in the Venn Diagram, we have subtracted $n(S\cap F \cap R)=x$ from each of the intersection of two sets.

The next step is to determine the number of students who study only each of the courses.

$n(S\:only)=1232-[103-x+x+23-x]=1106+x\\n(F\: only)=879-[103-x+x+14-x]=762+x\\n(R\:only)=114-[23-x+x+14-x]=77+x$

These values are substituted in the second Venn diagram

Adding up all the values

2092=[1106+x]+[103-x]+x+[23-x]+[762+x]+[14-x]+[77+x]

2092=2085+x

x=2092-2085

x=7

The number of students who have taken courses in all three subjects, $n(S\cap F \cap R)=7$

3 0

3 years ago