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Tamiku [17]
3 years ago
8

Yul and Sarah's art class started at 11:25 A.M.The class lasted 30 minutes. Yulieft when the class was done. Sarah stayed an ext

ra 5 minutes to talk with the teacher and then left. Write the time that each student left.Explain how you found each time.
Mathematics
1 answer:
tatuchka [14]3 years ago
7 0
We know that class starts 11:25 AM (be sure to note that there are only 60 minutes in an hour).
We know that class lasts 30 minutes.

First of all, let's find the time class ends.
11:25 AM (class starts) + 00:30 (minutes) = 11:55 AM (class ends)

Let's start with Yul's time first.
We know that Yul left when class was done, the time was already calculated when we added the time the class started with the time the class lasted and we got (in the previous line) 11:55 AM was when class ended, therefore, Yul left at 11:55 AM.

Sarah stayed an extra 5 minutes.
Class ended 11:55 AM. Simply add 5 minutes (00:05) to 11:55 AM.
11:55 AM (time class ended) + 00:05 (extra time to talk with the teacher) = 12:00 PM. Therefore, Sarah left at 12:00 PM.

As stated in the beginning of this problem, each hour only lasts 60 minutes, not 100 minutes, so every time the minutes are at the 60 tick mark, a new hour starts (in this case, 12:00 PM).

Yul left at 11:55 AM.
Sarah left at 12:00 PM.
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Hence, the question has the dimensions of the two adjacent sides of the right angle (angle 90°)

From Pythagoras theorem, we have;

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∠A is the side opposite side BC such that by trigonometric ratios

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