$\bf ~~~~~~ \textit{Continuously Compounding Interest Earned Amount} \\\\ A=Pe^{rt}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$800\\ r=rate\to 3.1\%\to \frac{3.1}{100}\dotfill &0.031\\ t=years\dotfill &20 \end{cases} \\\\\\ A=800e^{0.031\cdot 20}\implies A=800e^{0.62} \\\\\\ A\approx 1487.14\implies A=\stackrel{rounded~up}{1500}$

8 0

4 years ago

Allison measured a line to be 19.4 inches long. If the actual length of the line is 19.1

Lelu [443]

It can be noted that the percentage error made by Allison will be 1.6%

<h3>How to solve the percentage</h3>

From the information given, Allison measured a line to be 19.4 inches long and the actual length of the line is 19.1.

Therefore, the percentage error will be:

= (19.4 - 19.1)/19.1 × 100

= 0.3/19.1 × 100

= 1.6%

In conclusion, the correct option is 1.6%.

Learn more about percentages on:

brainly.com/question/24304697

5 0

3 years ago

How do i identify constants -((3y^3)/7)​

How do i identify constants -((3y^3)/7)