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2 years ago

Please help ASAP 25 pts + brainliest to right/best answer

Mathematics

1 answer:

BigorU [14]2 years ago

4 0

Answer:

Step-by-step explanation:

write in exponential form

log2(2^-1)

simplify

-1

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Complete the division problem by determining the number that should be placed in the box.

Damm [24]

Answer: 560

Step-by-step explanation:

547

14 | 7658

-7000

________

- 560

___________

- 98

__________

hope that helps i hope it correct and helps :D

8 0

2 years ago

What is the number −37,860,000 written in scientific notation?

Volgvan

Answer:

The answer is D - 3.786x10^7

7 0

2 years ago

Solve the quadratic equation algebraically 5-x<2(x-3)+5

vodka [1.7K]

Answer:

x>2

Step-by-step explanation:

5-x<2(x-3)+5

5-x<2x-6+5

5-x<2x-1

6-x<2x

6<3x

x>2

7 0

2 years ago

Helphelphelphelphelp

VashaNatasha [74]

The ratio is supposed to be pennies to total amount of coins. The total amount of coins--including pennies--is 16. This can be proven by this equation:

5 + 6 + 5 = 16

Now you put the ratio together by taking the amount of pennies (5) and total amount of coins (16). Your ratio should look like this:

5:16

Hope I helped you out! ❤❤

4 0

3 years ago

Sketch the equilibrium solutions for the following DE and use them to determine the behavior of the solutions.

GREYUIT [131]

Answer:

$y=\dfrac{1}{1-Ke^{-t}}$

Step-by-step explanation:

Given

The given equation is a differential equation

$\dfrac{dy}{dt}=y-y^2$

$\dfrac{dy}{dt}=-(y^2-y)$

By separating variable

⇒ $\dfrac{dy}{(y^2-y)}=-t$

$\left(\dfrac{1}{y-1}-\dfrac{1}{y}\right)dy=-dt$

Now by taking integration both side

$\int\left(\dfrac{1}{y-1}-\dfrac{1}{y}\right)dy=-\int dt$

⇒ $\ln (y-1)-\ln y=-t+C$

Where C is the constant

$\ln \dfrac{y-1}{y}=-t+C$

$\dfrac{y-1}{y}=e^{-t+c}$

$\dfrac{y-1}{y}=Ke^{-t}$

$y=\dfrac{1}{1-Ke^{-t}}$

from above equation we can say that

When t will increases in positive direction then $e^{-t}$ will decreases it means that ${1-Ke^{-t}}$ will increases, so y will decreases. Similarly in the case of negative t.

4 0

3 years ago