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aleksklad [387]
3 years ago
14

I need help I don't understand this

Mathematics
1 answer:
kaheart [24]3 years ago
7 0
What part do you not understand?
You might be interested in
► 00:00
SSSSS [86.1K]

Answer:

16 oz, 12 oz, 4 oz

Step-by-step explanation:

Since 1 pound is equal to 16 ounces, and you can only use each weight once or not at all, you can determine how much is needed by simply adding.

2 pounds is equal to 32 ounces.

To achieve 32 ounces, you can use a 16 ounce weight, which will then bring the scale to need 16 ounces.

After this you can youse a 12 ounce weight, which brings it down to 4 ounces.

The last weight needed is the 4 ounce weight which will then level out the balance scale.

8 0
4 years ago
For the equation given below, evaluate y′ at the point (−2,−1).<br><br> 3xy−3x−12=0.
SSSSS [86.1K]

Answer:

Y'=3xy-3x-12

Y'=F(-2,-1)=0

Step-by-step explanation:

The function of the equation at the point (-2,-1)

is where the equation make the function go to zero:

Y'=3xy-3x-12

Y'=F(-2,-1)=[3(-2)(-1)]-[3(-1)]-12

F(-2,-1)=[6]-[-6]-12

F(-2,-1)=6+6-12

F(-2,-1)=12-12

F(-2,-1)=0

Solving for y

3xy-3x-12=0

y=4/x+x

Making y=0

\frac{4}{x}+x=0

x^{2} =-4

x=-2

So the values make the function go to zero

3 0
3 years ago
Juna travels 15 mph for 10 hours find the distance piles per hour
marta [7]

Answer:2 hours 15 mins = 2 1/4 hours

2 1/4 hours = 25 miles

1 hour = 25 ÷ 2 1/4 = 25 ÷ 9/4 = 25 x 4/9 = 11.1 miles

Answer: 11.1 mph

Step-by-step explanation:

7 0
3 years ago
Show that the relation R consisting of all pairs(x, y)such that x and y are bit strings of length three or more that agree in th
Mice21 [21]

Answer:

See proof below

Step-by-step explanation:

An equivalence relation R satisfies

  • Reflexivity: for all x on the underlying set in which R is defined, (x,x)∈R, or xRx.
  • Symmetry: For all x,y, if xRy then yRx.
  • Transitivity: For all x,y,z, If xRy and yRz then xRz.

Let's check these properties: Let x,y,z be bit strings of length three or more

The first 3 bits of x are, of course, the same 3 bits of x, hence xRx.

If xRy, then then the 1st, 2nd and 3rd bits of x are the 1st, 2nd and 3rd bits of y respectively. Then y agrees with x on its first third bits (by symmetry of equality), hence yRx.

If xRy and yRz, x agrees with y on its first 3 bits and y agrees with z in its first 3 bits. Therefore x agrees with z in its first 3 bits (by transitivity of equality), hence xRz.

5 0
3 years ago
I need to know what's 1131÷29 pronto
Ivahew [28]

the answer is 39 because you need to divide.

6 0
3 years ago
Read 2 more answers
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