Ask question

Ask question

All categories

3 years ago

10

I mark as brainliest

1 answer:

noname [10]3 years ago

8 0

Answer:

- 1/4

Step-by-step explanation:

You might be interested in

PLEASE HELP ME! I NEED THIS BY TODAY

mrs_skeptik [129]

Answer: this is a INVERSE choice C

5 0

2 years ago

Read 2 more answers

Choose the expressions that are equivalent to m∠AOB. Select all that apply.

Tanzania [10]

Answer:

A, B, D, G, and H should be correct

Step-by-step explanation:

I've done the same problem and those were the answers shown

6 0

3 years ago

Read 2 more answers

Which relation does not represent a function

Nastasia [14]

Answer:

For example, if given a graph, you could use the vertical line test; if a vertical line intersects the graph more than once, then the relation that the graph represents is not a function.

Hope this helped

3 0

3 years ago

Maya has 760 carrots. 27% of them went rotten. What number of the carrots ARE'NT rotten?

Alja [10]

Answer:

About 554 carrots aren't rotten.

Step-by-step explanation:

100% - 27% = 73%

73% = 0.73

760 x 0.73 = 554.80

3 0

3 years ago

Read 2 more answers

Which expression represents the number 2i4−5i3+3i2+−81‾‾‾‾√ rewritten in a+bi form?

vichka [17]

Answer:

The expression $-1+14i$ represents the number $2i^4-5i^3+3i^2+\sqrt{-81}$ rewritten in a+bi form.

Step-by-step explanation:

The value of $i$ is $i=\sqrt{-1}[tex] or [tex]i^{2}=-1[\tex].Now [tex]i^{4}$ in term of $i^{2}[\tex] can be written as, [tex]i^{4}=i^{2}\times i^{2}$

Substituting the value,

$i^{4}=\left(-1\right)\times \left(-1\right)$

Product of two negative numbers is always positive.

$\therefore i^{4}=1$

Now $i^{3}$ in term of $i^{2}[\tex] can be written as, [tex]i^{3}=i^{2}\times i$

Substituting the value,

$i^{3}=\left(-1\right)\times i$

Product of one negative and one positive numbers is always negative.

$\therefore i^{3}=-i$

Now $\sqrt{-81}$ can be written as follows,

$\sqrt{-81}=\sqrt{\left(81\right)\times\left(-1\right)}$

Applying radical multiplication rule,

$\sqrt{ab}={\sqrt{a}}\sqrt{b}$

$\sqrt{\left(81\right)\times\left(-1\right)}={\sqrt{81}}\sqrt{-1}$

Now, $\sqrt{\left(81\right)=9$ and $\sqrt{-1}}=i$

$\therefore \sqrt{\left(81\right)\times\left(-1\right)}=9i$

Now substituting the above values in given expression,

$2i^4-5i^3+3i^2+\sqrt{-81}=2\left(1\right)-5\left(-i\right)+3\left(-1\right)+9i$

Simplifying,

$2+5i-3+9i$

Collecting similar terms,

$2-3+5i+9i$

Combining similar terms,

$-1+14i$

The above expression is in the form of a+bi which is the required expression.

Hence, option number 4 is correct.

5 0

3 years ago