Answer:
- The graph of y > 3x − 4 has shading above a dashed line.
- The graph of y < x + 1 has shading below a dashed line.
- The graphs of the inequalities will intersect.
Step-by-step explanation:
y > ... means the shading will be above the corresponding line.
y < ... means the shading will be below the corresponding line.
These lines have different slopes, so the solution spaces <em>must</em> overlap, hence <em>there must be solutions</em> to the system.
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<em>Comment on last choice</em>
It isn't clear exactly what is intended by the last offered statement. Both of the listed points are in the solution space of y > 3x-4. Neither point is in the solution space of y < x+1.
Together, the two graphs intersect the entire y-axis. Jointly, they only intersect the y-axis on the interval -4 < y < 1.
The y-intercepts of the two boundary lines are (0, 1) and (0, -4). Neither of these points is in the solution space of the system of inequalities.
Let’s start by stating the formula for the area of a rectangle,
A=LW
the letter a represents area, l represents length, and w represents width.
Next let’s substitute known values.
A=x(x+10)
Next let’s use the distributive property
A=(x(x))+(10(x))
Now simplify.
A=x^2 + 10x
So the equation for the area of this rectangle is A=x^2+10x
I believe this is the most simplified answer, please tell me if I am wrong and I will redo my work.
Answer:
y = 8x - 6
Step-by-step explanation:
find the common difference (+ or -) / ratio (x or ÷)
34 - 26 = 8
42 - 34 = 8
50 - 42 = 8
58 - 50 = 8
the common difference is 8
y = 8x + b
plug in an (x, y) value to find b
(7, 500
50 = 8(7) + b
50 = 56 + b
b = -6
y = 8x - 6