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Tomtit [17]
4 years ago
10

Evaluate 7y+13-4z when y=5 and z=9

Mathematics
2 answers:
torisob [31]4 years ago
8 0
7y + 13 - 4z
We have y=5 and z =9.
Everything you need to do is replace y by it's value, and z by it's value, and calculate following the orders of operations.
7*5 + 13 - 4*9
First, you calculate the multiplications, then you subtract and add.
35 + 13 - 36 = -1 + 13 = 12

Hope this Helps! :)
Gwar [14]4 years ago
6 0
7y add 13 minus 4z Y=5 z=9 7 times y=35 4 times z=36 35 add 13 minus 36 35 add 13=48 48 minus 36=12 Answer=12
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I WILL GIVE BRAINLEST!!! (6 points!)
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Answer:

OPTION A: 2x + 3y = 5

Step-by-step explanation:

The product of slopes of two perpendicular lines is -1.

We rewrite the given equation as follows:

2y = 3x + 2

⇒ y = $ \frac{3}{2}x + 1 $

The general equation of the line is: y = mx + c, where 'm' is the slope of the line.

Here, m = $ \frac{3}{2} $.

Therefore, the slope of the line perpendicular to the line given = $ \frac{-2}{3} $ because $ \frac{3}{2} \times \frac{-2}{3} = -1 $.

To determine the equation of the line passing through the given point and a slope we use the Slope - One - point formula which is:

                                  y - y₁ = m(x - x₁)

The point is: (x₁, y₁) = (-2, 3)

Therefore, the equation is:

y - 3 = $ \frac{-2}{3} $(x + 2) $

⇒ 3y - 9 = -2(x + 2)

⇒ 3y - 9 = -2x - 4

⇒ 2x + 3y = 5 is the required equation.

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Answer:

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1/cotθ

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