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djverab [1.8K]
3 years ago
6

Find the square root of 22​

Mathematics
2 answers:
Pani-rosa [81]3 years ago
8 0

Answer:

4.69041575982

Step-by-step explanation:

dusya [7]3 years ago
5 0

Answer:

4.6

Step-by-step explanation:

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If x−2=13, then what is the value of x2−4x+4?
Rus_ich [418]

Answer:

169

Step-by-step explanation:

x−2=13

First find the value of x

x-2+2 = 13+2

x = 15

Now substitute into the expression

x^2 -4x+4

15^2 -4*15+4

225 - 60+4

165+4

169

8 0
3 years ago
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mestny [16]
The correct answer is B) 1.15 seconds.
8 0
3 years ago
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crimeas [40]

Answer:

A. x≥4 ( red on 4)

B. x≤4 ( red on 4)

C. x>4 (blue on 4)

D. x<4 (blue on 4)

Step-by-step explanation:

illustrated

A. x≥4 ( red on 4)

B. x≤4 ( red on 4)

C. x>4 (blue on 4)

D. x<4 (blue on 4)

4 0
3 years ago
Read 2 more answers
Use an algebraic approach to solve the problem.
qaws [65]

Answer:

Her first exam score was a 78, her second exam score was a 89, and his third exam score was a 94.

Step-by-step explanation:

Use the formula for the mean: sum of elements / number of elements

Let x represent her first exam score.

Her second exam score can be represented by x + 11, since it was 11 points better than her first.

Her third exam score can be represented by (x + 11) + 5, since it was 5 points better than her second.

Plug in all of these expressions into the mean formula. Plug in 87 as the mean, and plug in 3 as the number of elements (since there are 3 scores):

mean = sum of elements / number of elements

87 =  ( (x) + (x + 11) + (x + 11) + 5 ) / 3

Add like terms and solve for x:

87 = (3x + 27) / 3

261 = 3x + 27

234 = 3x

78 = x

So, her first score was a 78.

Find her second score by adding 11 to this:

78 + 11 = 89

Find her third score by adding 5 to the second score:

89 + 5 = 94

Her first exam score was a 78, her second exam score was a 89, and his third exam score was a 94.

6 0
3 years ago
Graph y = -1/4x + 6. Please help!!
OverLord2011 [107]

Answer:

6  1/4

Step-by-step explanation:

6 0
3 years ago
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