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3 years ago

6

At the end of last year mark odometer reads 74,924 miles.at the end of this year , his odometer. reads 90,405 miles. How many mi

les Did Mark drive this year?

1 answer:

maks197457 [2]3 years ago

6 0

Mark drove 165,329 miles year

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The sale price of a bicycle is $130 this is 60% of the original price. find the original price

WITCHER [35]

$208

Steps:
10% of 130 is 13
13 x 6 would give you 60%
13 x 6 is 78
60% = 78
130 + 78 = 208

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3 years ago

Read 2 more answers

A 540-acre piece of land is being divided into 6-acre parcels. how many parcels will there be?

ryzh [129]

Basically, what you will do is 540 divided by 6

When you divide that, you should get, 90 parcels.

Hope this helps! Have a good rest of your day! c:

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3 years ago

Describe the meaning of the rate.

Usimov [2.4K]

Meaning of the rate: 6 days each month.
The answer is A. Something happens 6 days per month.
This means that in every month, there are available 6 days that let you do something.
Example in the GYm, you have 6 days per month free gym usage.

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4 years ago

On the graph shown, what is the slope ?

mr_godi [17]

Answer:

3/4

Step-by-step explanation:

To find the slope using a line on a graph, calculate the difference between two points. To do so, use the formula y2 - y1/x2 - x1.

Two points on this line are (0, -1) and (4, 2). This means:

y2 = 2

y1 = -1

x2 = 4

x1 = 0

Plugging those values in, we get:

2 - (-1)/4 - 0

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3 years ago

Assuming boys and girls are equally likely, find the probability of a couple having a baby girl when their sixth child is born

Ivanshal [37]

Answer: The required probability of having 6th girl is 0.5.

Step-by-step explanation: Given that boys and girls are equally likely.

We are to find the probability of a couple having a baby girl when their sixth child is born, given that the first five children were all girls.

Since the events of having a boy and a girl are independent of each other, so

the probability of having 6th girl dose not depend on the birth of the first five girls.

We know that there are only two possible cases (either a boy or girl will born).

So, sample space, S = {G, B} and the event E of having a girl is, E = {G}.

That is, n(S) = 2 and n(E) = 1.

Therefore, the probability of event E is given by

$P(E)=\dfrac{n(E)}{n(S)}=\dfrac{1}{2}=0.5.$

Thus, the required probability of having 6th girl is 0.5.

3 0

3 years ago