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Fynjy0 [20]
3 years ago
14

I need help quickly please have clear explanation and answer written in brainly

Mathematics
2 answers:
gregori [183]3 years ago
8 0
2 = 3

2 x 11 = 22
22 - 19 = 3

3 = 14

3 x 11 = 33
33 - 19 = 14

6 = 47

6 x 11 = 66
66 - 19 = 47

10 = 91

10 x 11 = 110
110 - 19 = 91
Andrei [34K]3 years ago
4 0

Answer:

ii

Step-by-step explanation:

i

You might be interested in
Kesha threw her baton up in the air from the marching band platform during practice. The equation h(t) = −16t² + 54t + 40 gives
lapo4ka [179]

Answer:

a) 40 feet

b) 54 ft/min

c) 4 mins

Step-by-step explanation:

Solution:-

- Kesha models the height ( h ) of the baton from the ground level but thrown from a platform of height hi.

- The function h ( t ) is modeled to follow a quadratic - parabolic path mathematically expressed as:

                           h ( t ) = −16t² + 54t + 40

Which gives the height of the baton from ground at time t mins.

- The initial point is of the height of the platform which is at a height of ( hi ) from the ground level.

- So the initial condition is expressed by time = 0 mins, the height of the baton h ( t ) would be:

                         h ( 0 ) = hi = -16*(0)^2 + 54*0 + 40

                         h ( 0 ) = hi = 0 + 0 + 40 = 40 feet

Answer: The height of the platform hi is 40 feet.

- The speed ( v ) during the parabolic path of the baton also varies with time t.

- The function of speed ( v ) with respect to time ( t ) can be determined by taking the derivative of displacement of baton from ground with respect to time t mins.

                        v ( t ) = dh / dt

                        v ( t )= d ( −16t² + 54t + 40 ) / dt

                        v ( t )= -2*(16)*t + 54

                        v ( t )= -32t + 54

- The velocity with which Kesha threw the baton is represented by tim t = 0 mins.

Hence,

                        v ( 0 ) = vi = -32*( 0 ) + 54

                        v ( 0 ) = vi = 54 ft / min

Answer: Kesha threw te baton with an initial speed of vo = 54 ft/min

- The baton reaches is maximum height h_max and comes down when all the kinetic energy is converted to potential energy. The baton starts to come down and cross the platform height hi = 40 feet and hits the ground.

- The height of the ball at ground is zero. Hence,

                     h ( t ) = 0

                     0 = −16t² + 54t + 40

                     0 = -8t^2 + 27t + 20

- Use the quadratic formula to solve the quadratic equation:

                     

                    t = \frac{27+/-\sqrt{27^2 - 4*8*(-20)} }{2*8}\\\\t = \frac{27+/-\sqrt{1369} }{16}\\\\t = \frac{27+/-37 }{16}\\\\t =  \frac{27 + 37}{16} \\\\t = 4

Answer: The time taken for the baton to hit the ground is t = 4 mins

3 0
3 years ago
What would be the answer
sashaice [31]

Answer:

I think It's option (B) 45

Step-by-step explanation:

But I am not sure It's correct or not

I hope It's helpful

6 0
3 years ago
Please answer tomorrow is my exam please​
Illusion [34]

Answer:

i dont know sorry.

Step-by-step explanation:

Do it yourself ;)

4 0
3 years ago
Evaluate the expression. ​ (26÷13)⋅(−7)+14−4 ​
Bas_tet [7]
Follow pemdas. Evaluate operations in parentheses first.
2*(-7)+14-4

Then multiply
-14+14-4

Then add and subtract from left to right
-14+14=0
0-4=-4

Final answer: -4
6 0
3 years ago
Read 2 more answers
Solve for x. Round your answer to the nearest tenth. 19, 17
luda_lava [24]

Step-by-step explanation:

since what ? there is nothing here.

3 0
3 years ago
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