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3 years ago

The measure of angle 3 is 42° What is the measure of angle 1 in degrees

Mathematics

1 answer:

OlgaM077 [116]3 years ago

4 0

Answer:

48 degrees

Step-by-step explanation:

Angle 2 is a right angle.

Right angles are 90 degrees.

A line is 180 degrees.

Angle 1, 5, and 2 form a line.

180-90=90

That means that Angles 1 and 5 add up to 90 degrees.

We know that Angle 3 is 42 degrees.

Angle 3 and 5 are Vertical angles.

Vertical angles are always congruent.

This means that Angle 5 is also 42 degrees.

As we discussed earlier, Angles 1 and 5 are complementary. (Add up to 90 degrees)

42+x=90

Subtract 42 from both sides.

x=48

m<1=48

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3 years ago

Give the largest interval over which the general solution is defined. (Think about the implications of any singular points. Ente

Leto [7]

Complete Question

The complete question is shown on the first uploaded image

Answer:

No singular point due to the exponent in the solution

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Step-by-step explanation:

From the question we are told that

$\frac{dy}{dx} = 9y$

The generally solution is mathematically represented as

$\frac{dy }{dx} = 9y$

=> $\frac{dy}{y} = 9dx$

integrating both sides

$\int\limits {\frac{ dy}{y} } \, = \int\limits {9} \, dx$

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=> $y = e^{9x +c }$

=> $y = e^{9x} e^{c}$

Here $e^c = C$

=> $y = C e^{9x}$

From the above equation we see that the domain for x has no singular point the interval is

$-\infty$

Also there is no transient term in the general solution obtained because as $x \to \infty$ there no case where $y \to 0$

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3 years ago

If 3x + 2 = 4, what is the value of 6x - 4?<br> 2<br> 8<br> 0<br> -2

Sladkaya [172]

Answer:

Step-by-step explanation:

3x + 2 = 4

4-2 = 3x

2 = 3x

x = 2/3

2/3 x 6 = 12/3 = 4 - 4 = 0

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3 years ago

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The 3rd one because of the laws and newton’s ways

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4 years ago

Consider the following set of equations, where s, s0, x and r have units of length, t has units of time, v has units of velocity

Anna11 [10]

Answer:

Step-by-step explanation:

For an equation to be dimensionally correct the dimension of quantities on both sides of equation must be same.

Also, two physically quantities can only be added or subtracted only when their dimension are same.

here all option are dimensionally correct except the 5th option where

dimension of t= [T] whereas dimension of a/v is $\frac{LT^{-2}}{LT^{-1}}$

= T^{-1}

since, the dimension of quantities on either sides of equation are not the same the equation is dimensionally is incorrect.

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3 years ago