Question

You work as a cashier for a bookstore and earn $6 per hour. You also baby sit and earn $6 per hour. You want to earn at least $60 per week, but would like to work no more than 12 hours per week.
Which system of inequalities, along with y ≥ 0 and x ≥ 0, would you use to solve the real-world problem?

Answer 1

Answer:

$6x + 6y \geq 60$

$x +y \leq 12$

$x\geq 0$

$y\geq 0$

Step-by-step explanation:

Call x the number of hours you work in the library

Let's call y the number of hours that you work as babysitter

You need to earn more than $ 60 per week, then:

$6x + 6y \geq 60$

You want to work no more than 12 hours per week. So:

$x +y \leq 12$

Finally, the system of inequalities that you will obtain is:

$6x + 6y \geq 60$

$x +y \leq 12$

$x\geq 0$

$y\geq 0$