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3 years ago

Simplify 8/12 completely. 6/10 O 4/8 2/3 O 4/6

Mathematics

2 answers:

Vinil7 [7]3 years ago

4 0

Answer:

he fraction 8/12 simplified is equal to 2/3.

Step-by-step explanation:

The solution to this problem can be found by first figuring out the greatest common denominator between.

Oksanka [162]3 years ago

4 0

8/12 is simplified to 2/3

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True or False, Intrusive rocks have large crystals?

Sladkaya [172]

<h2>Answer:</h2>

<h2>Step-by-step explanation:</h2>

<h3>Intrusive rocks, have large crystals that are usually visible without a microscope. </h3>

<h2>Therefore it's true. </h2>

4 0

2 years ago

Assume Cylinder A and Cone B are the same height and the bases have the same radius. If A has a volume of 18π cm3, what is the v

disa [49]

Answer:

Option A $V_B=19\ cm^3$

Step-by-step explanation:

The volume of a cone is:

$V_B = \pi\frac{hr ^ 2}{3}$

The volume of a cylinder is:

$V_A = \pi(r ^ 2)h$

Both figures have the same height h and the same radius r.

The volume of the cylinder $V_A = 18\pi\ cm ^ 3$

We want to find the volume of the cone.

Then, we find r and h:

$V_A = 18\pi = \pi(r ^ 2)h$

We simplify.

$V_A = 18 = (r ^ 2)h$

Then the product of $(r ^ 2)h = 18$ .

We substitute this in the cone formula and get:

$V_B =\frac{\pi}{3}(18)\\\\V_B = \frac{18}{3}\pi\\\\V_B=19\ cm^3$

8 0

3 years ago

Read 2 more answers

Which angles are congruent in the isosceles triangle?

zhannawk [14.2K]

Answer:

A. Angle CAB and angle BCA

Step-by-step explanation:

Hope it helps you in your learning process.

8 0

2 years ago

1. -2x(x+3)-(x+1)(x-2) =

Simora [160]

Answer:

$-3x^2 -7x + 2$

Step-by-step explanation:

Given

$-2x(x + 3) - (x+1)(x - 2)$

Required

Solve

Open brackets

$-2x^2 -6x - (x^2-2x + x - 2)$

$-2x^2 -6x - x^2-2x + x + 2$

Collect like terms

$- x^2-2x^2 -6x -2x + x + 2$

$-3x^2 -7x + 2$

5 0

2 years ago

in exercises 15-20 find the vector component of u along a and the vecomponent of u orthogonal to a u=(2,1,1,2) a=(4,-4,2,-2)

Nimfa-mama [501]

Answer:

The component of $\vec u$ orthogonal to $\vec a$ is $\vec u_{\perp\,\vec a} = \left(\frac{9}{5},\frac{6}{5},\frac{9}{10},\frac{21}{10}\right)$ .

Step-by-step explanation:

Let $\vec u$ and $\vec a$ , from Linear Algebra we get that component of $\vec u$ parallel to $\vec a$ by using this formula:

$\vec u_{\parallel \,\vec a} = \frac{\vec u \bullet\vec a}{\|\vec a\|^{2}} \cdot \vec a$ (Eq. 1)

Where $\|\vec a\|$ is the norm of $\vec a$ , which is equal to $\|\vec a\| = \sqrt{\vec a\bullet \vec a}$ . (Eq. 2)

If we know that $\vec u =(2,1,1,2)$ and $\vec a=(4,-4,2,-2)$ , then we get that vector component of $\vec u$ parallel to $\vec a$ is:

$\vec u_{\parallel\,\vec a} = \left[\frac{(2)\cdot (4)+(1)\cdot (-4)+(1)\cdot (2)+(2)\cdot (-2)}{4^{2}+(-4)^{2}+2^{2}+(-2)^{2}} \right]\cdot (4,-4,2,-2)$

$\vec u_{\parallel\,\vec a} =\frac{1}{20}\cdot (4,-4,2,-2)$

$\vec u_{\parallel\,\vec a} =\left(\frac{1}{5},-\frac{1}{5},\frac{1}{10},-\frac{1}{10} \right)$

Lastly, we find the vector component of $\vec u$ orthogonal to $\vec a$ by applying this vector sum identity:

$\vec u_{\perp\,\vec a} = \vec u - \vec u_{\parallel\,\vec a}$ (Eq. 3)

If we get that $\vec u =(2,1,1,2)$ and $\vec u_{\parallel\,\vec a} =\left(\frac{1}{5},-\frac{1}{5},\frac{1}{10},-\frac{1}{10} \right)$ , the vector component of $\vec u$ is:

$\vec u_{\perp\,\vec a} = (2,1,1,2)-\left(\frac{1}{5},-\frac{1}{5},\frac{1}{10},-\frac{1}{10} \right)$

$\vec u_{\perp\,\vec a} = \left(\frac{9}{5},\frac{6}{5},\frac{9}{10},\frac{21}{10}\right)$

The component of $\vec u$ orthogonal to $\vec a$ is $\vec u_{\perp\,\vec a} = \left(\frac{9}{5},\frac{6}{5},\frac{9}{10},\frac{21}{10}\right)$ .

4 0

3 years ago