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Nimfa-mama [501]
3 years ago
14

I need help with this ASAP.

Mathematics
1 answer:
Tomtit [17]3 years ago
3 0

Answer:

Step 1 write the equation for perimeter (2L+2W =24)

Step 2 write the equation for area L x W = 32

Step 3 rewrite the equation of area so that one variable is on the right side L=32/W

Step 4 substitute L from step 3 into Equation 1 and simplify 2(32/W)+2W=24

Step 5 having found the width in step 4, use equation 3 to find the length

Step-by-step explanation:

<em>This is just added to show you how to solve but limit your answer to the answer above: rate brainliest please</em>

Area = L*W

Perimeter = 2(L+W)

So say L*W=32

and 2(L+W) = 24 which is 2L+2W =24

From area L=32/W

Then substitute it into perimeter

2(32/W)+2W=24 if you simplify this you get Width is 4 and 8

then length =32/W but W is 4 and 8 So L= 8 and 4

Meaning you have two options first rectangle is W=4 and L is 8, second triangle W=8 and Length=4


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Answer:

It takes 5 days to process an application.

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We have that number of requests per month would be equal 1600

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They tell us that everything must be in a number of 20 business days, therefore, the number of applications in one day would be:

1600/20 = 80

Which means that the time needed to finish an application is:

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3 years ago
Solve for y. Answer to the nearest tenth
AysviL [449]

Answer:

y = 11.5

Step-by-step explanation:

Given 2 secants from an external point to the circle.

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You are looking at the New York ball drop on New Year’s Eve at a distance of 100 m away from the base of the structure. If the b
Fofino [41]

The question is an illustration of related rates.

The rate of change between you and the ball is 0.01 rad per second

I added an attachment to illustrate the given parameters.

The representations on the attachment are:

\mathbf{x = 100\ m}

\mathbf{\frac{dy}{dt} = 2\ ms^{-1}} ---- the rate

\mathbf{\theta = \frac{\pi}{4}}

First, we calculate the vertical distance (y) using tangent ratio

\mathbf{\tan(\theta) = \frac{y}{x}}

Substitute 100 for x

\mathbf{y = 100\tan(\theta) }

\mathbf{\tan(\theta) = \frac{y}{100}}

Differentiate both sides with respect to time (t)

\mathbf{ \sec^2(\theta) \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot \frac{dy}{dt}}

Substitute values for the rates and \mathbf{\theta }

\mathbf{ \sec^2(\pi/4) \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot 2}

This gives

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\mathbf{ 2 \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot 2}

Divide both sides by 2

\mathbf{ \frac{d\theta}{dt} = \frac{1}{100} }

\mathbf{ \frac{d\theta}{dt} = 0.01 }

Hence, the rate of change between you and the ball is 0.01 rad per second

Read more about related rates at:

brainly.com/question/16981791

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