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Goryan [66]
3 years ago
7

HELPPPPP PLEASEeeeeee

Mathematics
2 answers:
lana [24]3 years ago
8 0

Answer:

This is an example of the commutative property.

Step-by-step explanation:

The only thing that has been changed here is the placement of the a. The commutative property states that you can flip-flop the numbers/variables and still get the same result.

Agata [3.3K]3 years ago
5 0

Answer:communitive property?

Step-by-step explanation: I’m kind of unsure, but the parenthesis are switching places so I think so. IM SO SORRY IF I MADE YOU GET THIS WRONG!!!

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How can i calculate the growth rate of the values below
Grace [21]

Answer:

  12%

Step-by-step explanation:

The equation for the growth is ...

  f(t) = (initial value)×(growth multiplier per period)^(number of periods)

where the growth multiplier is often expressed as a percentage added to 1:

  multiplier = 1+r

  growth rate = r

__

This equation has two unknowns:

  • initial value
  • growth multiplier

In order to find these, you can make use of two of the supplied data points. I like to choose the ones that are farthest apart, as they tend to average out any errors due to rounding.

Clearly, the table tells you the initial value is 210. If you don't believe, you can put the numbers in the equation to see that:

  f(0) = (initial value)×(growth multiplier)^0

  210 = (initial value)×1

  (initial value) = 210

__

Using the last data point, we get ...

  f(7) = 210×(growth multiplier)^7

  464 = 210×(growth multiplier)^7 . . . . . . . . . fill in table value

  2.209524 = (growth multiplier)^7 . . . . . . .  divide by 210

You can solve this a couple of ways. My calculator is able to take the 7th root, so I can use it to find ...

  \sqrt[7]{2.209524}=\text{(growth multiplier)}\\1.119916\approx \text{(growth multiplier)}

Alternatively, you can use the 1/7 power:

  2.209524^(1/7) = (growth multiplier)

Another way to solve this is to use logarithms:

  log(2.209524) = 7×log(growth multiplier) . . . . . take the log

  log(2.209524)/7 = log(growth multiplier) . . . . . divide by 7

  0.04918553 ≈ log(growth multiplier)

  growth multiplier = 10^0.04918553 ≈ 1.11992 . . . . take the antilog

So, our growth multiplier is ...

  1 + r ≈ 1.11992

  r ≈ .11992 ≈ 12.0%

The rate of growth is about 12% in each period.

_____

Collapsing all of that to a single calculation:

  growth rate = (464/210)^(1/(7-0)) -1 ≈ 12.0%

8 0
3 years ago
What is the SEC?
Ronch [10]
I believe it’s C!!!!
5 0
3 years ago
Read 2 more answers
Please help me I’ll give brainliest! ://
Karo-lina-s [1.5K]

Answer:

The answer would be -10x-9

4 0
3 years ago
Jonathan is driving to his grandma’s house. Jonathan’s car is going 75 mph and he has to go 340 miles still. Brighton, Jonathan’
Karo-lina-s [1.5K]

Answer:

Johanatho will get in 4.53 hours. joahnathons cousin will take 4.57 hours.

Step-by-step explanation:

340/75=4.53

320/70=4.57

3 0
3 years ago
Suppose that 15% of people dont show up for a flight, and suppose that their decisions are independent. how many tickets can you
geniusboy [140]

Answer: <em><u>157 tickets </u></em>

Explanation:

The people not showing up for the flight can be treated as from Binomial distribution.

The binomial distribution B(n, p) is approximately close to the normal i.e. N(np, np(1 − p))  for large 'n' and for 'p' and neither too close to 0 nor 1 .

Now, Let us assume 'n' = n

and we are given

p=0.15

So now B(n,0.15n) follows Normal distribution

u=n

\sigma^{2} = 0.15n

We have to calculate P(X<144) with 99% accuracy

P(X<144) = P(Z<z)

where;

z= (144-\bar{X})\div \sigma

z score for 99% is 2.33

i.e.  

(144-\bar{X})\div \sigma = (144-n)/\sqrt{np} = 2.33\\\ (144-n)^{2} = \ np*2.33^{2}\\\ 20736 +n^{2} - 288n = 0.15n*5.43\\\ n^{2} - 288.81n + 20736=0

solving this we will get one root nearly equal to 157 and other root as 133

<u><em>Hence the answer is 157.</em></u>

8 0
3 years ago
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