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STatiana [176]
3 years ago
15

The area of a square is 64n36 square units. What is the side length of one side of the square?

Mathematics
2 answers:
joja [24]3 years ago
5 0
The answer is 73.4..........
olya-2409 [2.1K]3 years ago
3 0

Answer:

73.4

Step-by-step explanation:

64 squared + 36 squared = c squared

  4096 + 1292 = c squared

5392 square rooted

73.7 as the answer

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A graph thAt has a finite or limited number of data points is
igor_vitrenko [27]

The <em>correct answer</em> is:


Discrete graph.


Explanation:


A discrete graph is a graph of disconnected points.


Since they are disconnected, this means the graph only has values at the points drawn, not between.


The opposite of a discrete graph is a continuous graph; it is a graph of connected points. Since the points are connected, the graph has values between all of the points. This is similar to what we learned in geometry about a line; a line has an infinite number of points. This is true of the connections between points in a continuous graph.


Since a discrete graph is the opposite of a continuous graph, this means it does <em>not</em> have an infinite number of points; a discrete graph has a <em>finite</em> number of points.

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3 years ago
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Dahasolnce [82]

Answer:

33

Step-by-step explanation:

you take the number used the most and that's your mode and you can have multiple but for this problem its 33

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3 years ago
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Calculate the following limit:
aleksklad [387]
\lim_{x\to\infty}\dfrac{\sqrt x}{\sqrt{x+\sqrt{x+\sqrt x}}}=\\&#10;\lim_{x\to\infty}\dfrac{\dfrac{\sqrt x}{\sqrt x}}{\dfrac{\sqrt{x+\sqrt{x+\sqrt x}}}{\sqrt x}}=\\&#10;\lim_{x\to\infty}\dfrac{1}{\sqrt{\dfrac{x+\sqrt{x+\sqrt x}}{x}}}=\\&#10;\lim_{x\to\infty}\dfrac{1}{\sqrt{1+\dfrac{\sqrt{x+\sqrt x}}{x}}}=\\&#10;\lim_{x\to\infty}\dfrac{1}{\sqrt{1+\dfrac{\sqrt{x+\sqrt x}}{\sqrt{x^2}}}}=\\
\lim_{x\to\infty}\dfrac{1}{\sqrt{1+\sqrt{\dfrac{x+\sqrt x}{x^2}}}}=\\\lim_{x\to\infty}\dfrac{1}{\sqrt{1+\sqrt{\dfrac{1}{x}+\dfrac{\sqrt x}{\sqrt{x^4}}}}}=\\\lim_{x\to\infty}\dfrac{1}{\sqrt{1+\sqrt{\dfrac{1}{x}+\sqrt{\dfrac{x}{x^4}}}}}=\\&#10;\lim_{x\to\infty}\dfrac{1}{\sqrt{1+\sqrt{\dfrac{1}{x}+\sqrt{\dfrac{1}{x^3}}}}}=\\&#10;=\dfrac{1}{\sqrt{1+\sqrt{0+\sqrt{0}}}}=\\
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8 0
3 years ago
You have a 36 foot fence that have a 4 equal side you painted 1/4 what fraction have you completed
k0ka [10]

we have completed 9/36=1/4 of the fence

5 0
3 years ago
John buys 3 pounds of cherries and 2 pounds of bananas he pays a total of $24.95 the bananas cost $6.50 less per pound than the
Murrr4er [49]

John will pay $8.68 for the combined cost of 1 pound of banana and 1 pound of cherries.

Let: b=cost of banana per pound and c=cost of cherries per pound

Equation 1: For 3 pounds of cherries and 2 pounds of bananas, John pays a total of $24.95.

3c + 2b =$24.95

Equation 2: The cost of bananas is $6.50 less than a pound of cherries.

b= c - $6.50

We can substitute the second equation into the first one to solve for the cost of cherries per pound.

3c + (2)(c-$6.50)= $24.95

3c + 2c -$13.00 = $24.95

5c = $24.95 + $13.00

c = $7.59

Substituting the value of c to the second equation to solve for b.

b= $7.59 - $6.50 = $1.09

The combined cost of 1 pound of banana and 1 pound of cherries is $1.09 + $7.59 or $8.68.

For more information regarding the system of equations, please refer to brainly.com/question/25976025.

#SPJ4

4 0
1 year ago
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