Answer:
<em>Hence the daughter's present age is 15 years</em>
<em>The fathers present age is 35 years</em>
<em></em>
Step-by-step explanation:
Let the present age of daughter be x
Let the present age of father be y
5 years ago;
Daughter's age = x - 5
Fathers age = y - 5
If the present age of father is thrice as old as the age of daughter 5 years ago, then;
y - 5 = 3(x-5)
y - 5 = 3x-15
y = 3x - 10 .... 1
In 5 years time;
Daughters age = x + 5
Fathers age = y + 5
If the age of father will be twice the age of his daughter in 5 years time then;
y+5 = 2(x+5)
y+5 = 2x + 10
y = 2x + 5 .....2
Equate 1 and 2;
3x - 10 = 2x + 5
3x - 2x = 5 + 10
x = 15
Since y = 2x + 5
y = 2(15) + 5
y = 35
<em>Hence the daughter's present age is 15 years</em>
<em>The fathers present age is 35 years</em>
<em></em>
This equation does not factor...
V=u + at
V - u = at divide both sides by
t
(V-u)/t =a
a = (v - u) /t
Answer: The value of A would be 2.
Answer:
(C) Nathaniel can build at most 3 birdhouses.
Step-by-step explanation:
Given that:
where:
- B represents the number of birds
- H represents the number of Birdhouses
Nathaniel wants to build 50 birds(B) using lego Blocks, we want to determine how many birdhouses(H) he can build with the remaining Lego blocks.
If B=50
Therefore, Nathaniel can build at most 3 Birdhouses.
