Question

Factor (3c–5)^2–16c^2

Answer 1

Here is your answer

${(3c - 5)}^{2} - {16c}^{2}$

$= {(3c - 5)}^{2} - {(4c)}^{2}$

$using \: identity \\ {a}^{2} - {b}^{2} = (a + b)(a - b)$

$(3c - 5 + 4c)(3c - 5 - 4c)$

$(7c - 5)( - c - 5)$

HOPE IT IS USEFUL