The sum of the lengths of the bases (b1+b2) for the given trapezoid is 10 meters.
<u>Step-by-step explanation:</u>
The given information are,
- The height of the parallelogram = 7 meters
- The area of the parallelogram = 35 square meters.
It is given that the height and area of the trapezoid is same as the height and area of the parallelogram.
<u>To find the sum of the lengths of the bases of trapezoid :</u>
Substitute height, h of the trapezoid as 7 meters and Area of trapezoid as 35 square meters.
Area of the trapezoid = 1/2 × h × (b1+b2)
35 = 1/2 × 7 × (b1+b2)
70/7 = (b1+b2)
(b1+b2) = 10
Therefore, the sum of lengths of the bases of trapezoid is 10 meters.
A foot is 12 inches... so it would be a foot
Answer:
y - 1 = - 4(x + 3)
Step-by-step explanation:
The equation of a line in point- slope form is
y - b = m(x - a)
where m is the slope and (a, b) a point on the line
Here m = - 4 and (a, b) = (- 3, 1), thus
y - 1 = - 4(x - (- 3)), that is
y - 1 = - 4(x + 3)
Https://answers.yahoo.com/question/index?qid=20120624121412AAV4Cjw
Hope that helps!
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Answer:

Step-by-step explanation:
Given that:

where;
the top vertex = (0,0,1) and the base vertices at (0, 0, 0), (1, 0, 0), (0, 1, 0), and (1, 1, 0)
As such , the region of the bounds of the pyramid is: (0 ≤ x ≤ 1-z, 0 ≤ y ≤ 1-z, 0 ≤ z ≤ 1)


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