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Marat540 [252]
3 years ago
13

Find the probability of spinning a number followed by a letter

Mathematics
1 answer:
777dan777 [17]3 years ago
8 0

Answer:

Answer is first option \dfrac{2}{9}.

Step-by-step explanation:

Let <em>A</em> be the event of spinning a number.

<em>P(A)</em> be the probability of spinning a number.

Here, total numbers in the game are 8.

Let <em>B</em> be the event of spinning a letter.

<em>P(B)</em> be the probability of spinning a letter.

Total number of letters is 4.

Total number of possibilities of a spin is 12.

Formula for probability of an event E can be observed as: P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}

\Rightarrow P(A) = \dfrac{8}{12}\\ \Rightarrow P(A) = \dfrac{2}{3}

Similarly

P(B) = \dfrac{4}{12}\\\Rightarrow P(B) = \dfrac{1}{3}

Here, events <em>A</em> and <em>B</em> are independent events and we have to find the probability of occurrence of both together. <em>i.e. </em>To find the probability of spinning a letter after a number.

Required probability can be achieved just by multiplying the probabilities of both the events.

\Rightarrow P(A)\times P(B)\\\Rightarrow \dfrac{2}{3} \times \dfrac{1}{3}\\\Rightarrow \dfrac{2}{9}

So, answer is first option \dfrac{2}{9}.

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Given k(x)=4x+5, if k(x)=-3 find x
zvonat [6]

Answer:

x=-5/7

Step-by-step explanation:

4 0
3 years ago
This is very confusing to me can someone help
fomenos
1. Is a right angle
2.is a obtuse.
5 0
3 years ago
Read 2 more answers
Two leprechauns are arguing over a pot of gold. The first leprechaun says to the other, ‘Give me seven of your gold pieces and I
Anvisha [2.4K]
Gold pieces the first leprechaun has: x
Gold pieces the second leprechaun has: y
<span>
The first leprechaun says to the other, ‘Give me seven of your gold pieces and I will have twice as many as you!’:
The first leprechaun would have x+7
The second leprechaun would have y-7
</span>I will have twice as many as you:
(1) x+7=2(y-7)
<span>(1) x+7=2y-14
(1) x+7-7-2y=2y-14-7-2y
(1) x-2y=-21

</span>The other one replies, ‘No way! Give me seven of yours and we’ll have the same number’
The first leprechaun would have x-7
The second leprechaun would have y+7
We’ll have the same number:
(2) x-7=y+7
(2) x-7+7-y=y+7+7-y
(2) x-y=14

<span>How many gold pieces does the first leprechaun have?
x=?
We have a system with 2 equations and two unknows (x and y). We need to solve for x:
(1) x-2y=-21
(2) x-y=14

Using the method of substitution, we can isolating y in the second equation:
(2) x-y=14
(2) x-y+y-14=14+y-14
(2) x-14=y
(2) y=x-14  

And we can replace y in the first equation by x-14, and solve for x: 
(1) x-2y=-21
(1) x-2(x-14)=-21
(1) x-2x+28=-21
(1) -x+28=-21
(1) -x+28-28=-21-28
(1) -x=-49
(1) (-1)*(-x=-49)
(1) x=49

Answer: T</span>he first leprechaun has 49 gold pieces

5 0
3 years ago
What's A(-2,-4),B(2,4)
dexar [7]
AB = \sqrt{( 2 + 2 ) ^{2} +  (4 + 4)^{2} } =  \sqrt{16 + 256} =  \sqrt{272} = 16.49
5 0
3 years ago
Use the Statistical Applet: P ‑Value for a Test of One Proportion to answer the question.You have taken a sample of ????=1000 in
umka21 [38]

Answer:

z=\frac{0.785 -0.7}{\sqrt{\frac{0.7(1-0.7)}{750}}}=5.08  

p_v =P(z>5.08)=1.88x10^{-7}  

So the p value obtained was a very low value and using the significance level assumed \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of interest is highr than 0.67 or 67% .  

Step-by-step explanation:

1) Data given and notation  

n=20 represent the random sample taken

X=15 represent the people who eat breakfast

\hat p=\frac{15}{20}=0.75 estimated proportion of people who eat breakfast

p_o=0.67 is the value that we want to test

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion is higher than 67%:  

Null hypothesis:p\leq 0.67  

Alternative hypothesis:p > 0.67  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.785 -0.7}{\sqrt{\frac{0.7(1-0.7)}{750}}}=5.08  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

p_v =P(z>5.08)=1.88x10^{-7}  

So the p value obtained was a very low value and using the significance level assumed \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of interest is highr than 0.67 or 67% .  

6 0
3 years ago
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