Answer:


Step-by-step explanation:
<u>Given function</u>:

If (x + 2) is a factor then:

Expand:



To find <em>a</em>, compare the coefficients of x³:

To find <em>b</em>, substitute the found value of <em>a</em> into the coefficient for x² and compare:



To find <em>c</em>, compare the constants:


Therefore:

Now factor (3x²-8x+5):



Therefore the factored function is:

<u>Zero Product Property</u>

To find the zeros, set each factor equal to zero and solve for x:



Therefore, the zeros of the function are:

 
        
             
        
        
        
Answer:
$112.80
Step-by-step explanation:
If he earns $0.235 per pack, and there are 480 packs, then our equation is:
0.235 x 480 = $112.80
 
        
             
        
        
        
To get an average score of 80% (out of four exams), a total of 4*80%=320% is needed, so the minimum required for the 4th test is 320-(75+97+60)=88.
To get an average score of 89% (out of four exams), a total of 4*89%=356% is needed, so the maximum required for the 4th test is 356-(75+97+60)=124, which is impossible.
So the next exam grade must range between 88 and 100 to get a grade b in the class.
Hoped I help! Mark brainly it would help<3
        
             
        
        
        


- <u>While </u><u>shopping </u><u>for </u><u>clothes </u><u>Tracey </u><u>spent </u><u>3</u><u>8</u><u>$</u><u> </u><u>less </u><u>than </u><u>3</u><u> </u><u>times </u><u>of </u><u>what </u><u>Daniel </u><u>spent </u>
 

- <u>We </u><u>have </u><u>to </u><u>determine </u><u>the </u><u>total </u><u>cost </u><u>spent </u><u>by </u><u>daniel</u>
 

Cost spent by Tracey for her clothes = 38$
Let assume the spending by Daniel is x 





 
        
             
        
        
        
The question is somehow incomplete but the answer is it in
the inferential stage of probability-based inference. It is in
complex networks of codependent variables is an lively theme in statistical
research, encouraged by such varied presentations as predicting, pedigree examination
and troubleshooting.