Please help find the percent of increase?!
1 answer:
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X miles per hour - <span> speed of the boat in still water
(x - 2) - speed up the river
(x + 2) - speed down the river
</span>
= 
30 * (x + 2) = 38 * (x - 2)
30x + 60 = 38x - 76
- 8x = - 136
x = 17 miles per hour - <span>the speed of the boat in still water.</span>
(x - 2) - speed up the river
(x + 2) - speed down the river
</span>
30 * (x + 2) = 38 * (x - 2)
30x + 60 = 38x - 76
- 8x = - 136
x = 17 miles per hour - <span>the speed of the boat in still water.</span>
Answer:
∠S = 21.10°
∠M = 79.45°
PM = 9.16
Step-by-step explanation:
Here Pythagorean theorem and trigonometry suffice to solve our problem.
From the Pythagorean theorem we get:
and
We solve for in the second equation and get:
Now since
Therefore
and
And finally again from the Pythagorean theorem:
Thus,
∠S = 21.10°
∠M = 79.45°
PM = 9.16.
Answer:
Whereby circle P can be obtained from circle
O by applying the transformations of a translation of T₍₁₄, ₋₈₎ followed by a dilation by a scale factor of 2.4,
O is similar to
P
Step-by-step explanation:
The given center of the circle O = (-2, 7)
The radius of O, r₁ = 5
The given center of the circle P = (12, -1)
The radius of P, r₂ = 12
The similarity transformation to prove that O and
P are similar are;
a) Move circle O 14 units to the right and 8 units down to the point (12, -1)
b) Apply a scale of S.F. = r₂/r₁ = 12/5 = 2.4
Therefore, the radius of circle O is increased by 2.4
We then obtain O' with center at (12, -1) and radius r₃ = 2.4×5 = 12 which has the same center and radius as circle
P
∴ Circle P can be obtained from circle
O by applying similarity transformation of translation of T₍₁₄, ₋₈₎ followed by a dilation by a scale factor of 2.4,
O is similar to
P.