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Irina-Kira [14]
3 years ago
14

Determine the equation of the line passing through the midpoint of the segment (-1 , 3) and (2 , -4) and that is parallel to the

line 2x - 4y = 11
Mathematics
1 answer:
kifflom [539]3 years ago
8 0

Answer:

2+3+87+748+7467++57-65488=20 that is the answer

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-4(8h-5)= -16 round to the nearnest hundreth
bezimeni [28]

Answer:

h=9/8 or 1.125 but since yo said round it's 1.13

Step-by-step explanation:

8 0
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Billy’s mother had five children. The first was named Lala, the second was named Lele, the third was named Lili, the fourth was
pantera1 [17]

Answer:

Billy

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come on really?

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3 years ago
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the distance from school to Zoie's house is 3km469m. Jamie's house is 4km301m farther away from Zoie's. How far is it from Jamie
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To travel from Jamies house to the school, you would have to travel is 7km770m.

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Question
34kurt

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4 years ago
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After being treated with chemotherapy, the radius of the tumor decreased by 23%. What is the corresponding percentage decrease i
Crazy boy [7]

Answer:

The volume of the tumor experimented a decrease of 54.34 percent.

Step-by-step explanation:

Let suppose that tumor has an spherical geometry, whose volume (V) is calculated by:

V = \frac{4\pi}{3}\cdot R^{3}

Where R is the radius of the tumor.

The percentage decrease in the volume of the tumor (\%V) is expressed by:

\%V = \frac{\Delta V}{V_{o}} \times 100\,\%

Where:

\Delta V - Absolute decrease in the volume of the tumor.

V_{o} - Initial volume of the tumor.

The absolute decrease in the volume of the tumor is:

\Delta V = V_{o}-V_{f}

\Delta V = \frac{4\pi}{3}\cdot (R_{f}^{3}-R_{o}^{3})

The percentage decrease is finally simplified:

\%V = \left[1-\left(\frac{R_{f}}{R_{o}}\right)^{3} \right]\times 100\,\%

Given that R_{o} = R and R_{f} = 0.77\cdot R, the percentage decrease in the volume of tumor is:

\%V = \left[1-\left(\frac{0.77\cdot R}{R}\right)^{3} \right]\times 100\,\%

\%V = 54.34\,\%

The volume of the tumor experimented a decrease of 54.34 percent.

5 0
3 years ago
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