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blagie [28]
3 years ago
14

The drama club is selling tickets to their play to raise money for the show's expenses.

Mathematics
1 answer:
xxTIMURxx [149]3 years ago
6 0

Answer:

250 $3 tickets and 100 $2 tickets were sold.

Step-by-step explanation:

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Can someone help me with this please?!?!?!?
dusya [7]
Answer

17 m^3

Explanation

Volume of a given prism = bh

Where b = base area and h = height of prism

Base area = 1 • 2/2 (b • h /2)

= 1

Height = 17

17 • 1 = 17 m^3
5 0
2 years ago
What is the range of function y=√(-2cos^2x+3cosx-1)
Ugo [173]
Hello Friend,here is the solution for your question


<span>so the given function is </span>
y= √(-2cos²x+3cosx-1)
 i.e = √[-2(cos²x-3/2+1/2)]
i.e = √[-2(cosx-3/4)²-9/16+1/2]
i.e. = √[-2(cos-3/4)²-1/16]
i.e. = √[1/8-3(cosx=3/4)²]-----------(1)

Now here  in this equation is this quantity :-
<span>(cosx=3/4)²----------------(2)   is to it's minimum value then the whole equation </span>
<span>i.e. = √[1/8-3(cosx=3/4)²] will be maximum and vice versa </span>


And we know that cosx-3/4 will be minimum if cosx=3/4
<span>therefore put this in (1) we get </span>
(cosx=3/4)²=0    [ cosx=3/4]
<span>hence the minimum value of the quantity (cosx=3/4)² is 0 </span>

<span>put this in equation (1) </span>
we get ,
i.e. = √[1/8-3(cosx=3/4)²]
   =√[1/8-3(0)]        [ because minimum value of of the quantity (cosx=3/4)² is 0 ]
     =√1/8
      =1/(2√2)

<span>this is the maximum value now to find the minimum value </span>

<span>since this is function of root so the value of y will always be ≥0 </span>

<span>hence the minimum value of the function y is 0 </span>


<span>Therefore, the range of function </span>y is [0,1/(2√2)]


__Well,I have explained explained each and every step,do tell me if you don't understand any step._

8 0
3 years ago
write an equation of a line with the given slope and y-intercept. m = –2, b = 4 y = 4x – 2 y = –2x – 4 y = -1/2x 4 y = –2x 4
kirill [66]
Y = mx + b

m = -2, b = 4

<span>y = -2x + 4</span>
4 0
3 years ago
Read 2 more answers
Using the numbers 3, 2, and 4, which of these problems would have a solution of 4?
Alexeev081 [22]
Pemdas

ok if we look at the first one
exponents first
2^3=8
2^3=8
we have
4*8/8
4*8=32
32/8=4
das is answer


the first one is the answer
7 0
3 years ago
If LM = MK, LK =7x-10, KN = x+3, MN = 9x-11, and KJ =28, find LJ
marusya05 [52]

Answer:


Step-by-step explanation:

Suppose J, K, L, M, N are points on the same line.


MK = MN + (-KN) = MN - KN = 9x - 11 - x - 3 = 8x - 14


Since LK = MK and LK = 7x - 10, then


7x - 10 = 8x - 14


8x - 7x = -10 + 14


x = 4


LJ = MK + KJ


MK = LK = 7x - 10 = 7(4) - 10 = 28 - 10 = 18


LJ = 18 + 28 = 46


Read more on Brainly.com - brainly.com/question/5067118#readmore

8 0
3 years ago
Read 2 more answers
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