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Kazeer [188]
3 years ago
14

What is the equivalent way to write the expression without grouping symbols?

Mathematics
1 answer:
Dimas [21]3 years ago
4 0
The correct answer is 6(2 - 3x) = 12 - 18x
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If I invest $3600 at an interest rate of 4% per year, and contribute an additional $30 per month, how much will I have in 5 year
SOVA2 [1]
Http://www.pierce.ctc.edu/staff/dlippman/mathinsociety/Finance1.0.pdf I think this will help
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4 years ago
I’m so confused. Someone please help and if you can explain how to do it. WILL MARK BRAINLIEST
blondinia [14]

Answer:

Function

Step-by-step explanation:

A function is a relation where each x-value has only one y-value. In this problem, all the x-values have a y-value of 3. It is a function because even though they all share the same y-value, they don't have more than one y-value. It would be a relation but not a function if one x-value had two y-values.

Hope this helps. :)

3 0
3 years ago
Due in 7 mins ASAP help plz
s344n2d4d5 [400]
Next is 32,-64
(-4,8,-16,32,-64)
The numbers double each time except it switches from negative to positive
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3 years ago
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Anon25 [30]

Answer: 7 1/2

Step-by-step explanation:

8 0
3 years ago
You believe the population is normally distributed. Find the 80% confidence interval. Enter your answer as an open-interval (i.e
victus00 [196]

You intend to estimate a population mean μ from the following sample. 26.2 27.7 8.6 3.8 11.6 You believe the population is normally distributed. Find the 80% confidence interval.  Enter your answer as an open-interval (i.e., parentheses) accurate to twp decimal places.

Answer:

The  Confidence interval = (8.98 , 22.18)

Step-by-step explanation:

From the given information:

mean = \dfrac{ 26.2+ 27.7+ 8.6+ 3.8 +11.6 }{5}

mean = 15.58

the standard deviation \sigma = \sqrt{\dfrac{\sum(x_i - \mu)^2 }{n}}

the standard deviation = \sqrt{\dfrac{(26.2  - 15.58)^2 +(27.7 - 15.58)^2 +(8.6  - 15.58)^2 + (3.8  - 15.58)^2  + (11.6  - 15.58)^2  }{5 }  }

standard deviation = 9.62297

Degrees of freedom df = n-1

Degrees of freedom df = 5 - 1

Degrees of freedom df = 4

For df  at 4 and 80% confidence level, the critical value t from t table  = 1.533

The Margin of Error M.O.E = t \times \dfrac{\sigma}{\sqrt{n}}

The Margin of Error M.O.E = 1.533 \times \dfrac{9.62297}{\sqrt{5}}

The Margin of Error M.O.E = 1.533 \times 4.3035

The Margin of Error M.O.E = 6.60

The  Confidence interval = ( \mu  \pm M.O.E )

The  Confidence interval = ( \mu  +  M.O.E , \mu - M.O.E )

The  Confidence interval = ( 15.58 - 6.60 , 15.58 + 6.60)

The  Confidence interval = (8.98 , 22.18)

7 0
3 years ago
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