Answer:
Therefore, equation of the line that passes through (16,-7) and is perpendicular to the line
is
Step-by-step explanation:
Given:
To Find:
Equation of line passing through ( 16, -7) and is perpendicular to the line
Solution:
...........Given

Comparing with,
Where m =slope
We get
We know that for Perpendicular lines have product slopes = -1.

Substituting m1 we get m2 as

Therefore the slope of the required line passing through (16 , -7) will have the slope,
Now the equation of line in slope point form given by
Substituting the point (16 , -7) and slope m2 we will get the required equation of the line,
Therefore, equation of the line that passes through (16,-7) and is perpendicular to the line
is
Answer:
Step-by-step explanation:
L1 -x + 2y = -1
L2 5x - 10y = 6
-x + 2y = - 1 multiply by -1
x - 2y = 1 multiply by 5
5x - 10y = 5 is similar that 5x - 10y = 6
The system has no solution
Answer:
C
Step-by-step explanation:
Just took it