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galina1969 [7]
3 years ago
7

1.) You need to buy grass seed for a new lawn. The lawn will cover a rectangular plot that is 60 feet by 90 feet. Each ounce of

grass seed will cover 120 square feet.
A.) how many ounces of grass seed will you need to buy?

B.) If the grass seed you want only comes in one-pound bags, how many bags will you need to buy?
Mathematics
2 answers:
galina1969 [7]3 years ago
7 0
Part A:
First, we will need to compute the area of the lawn.
We are given that the lawn is a rectangular plot with dimensions 60 ft and 90 ft.
Area of rectangle = length * width
Area of lawn = 60 * 90 = 5400 ft^2
Now, we will compute the number of ounces.
We are given that:
<span>Each ounce of grass seed will cover 120 square feet. Therefore, to know the number of ounces needed to cover 5400 square feet, all we have to do is cross multiplication as follows:
1 ounce ---------> 120 square feet
?? ounce --------> 5400 square feet
Number of ounces needed = (5400*1) / (120) = 45 ounces

Part B:
We know that one ounce is equivalent to 0.0625 pounds.
For the lawn, we need 45 ounces, this means that:
number of pounds needed for the lawn = (45*0.0625) / (1) = 2.8125 pounds
which is approximately 3 pounds.
We know that each bag weighs one pound, therefore:
number of bags needed = 3 bags

Hope this helps :)

</span>
MakcuM [25]3 years ago
3 0
Area = 60×90= 5400ft

A) Since 1 grass seed covered 120 ft of land.
5400÷120=45


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3. Write three ratios equal to 4/36
tia_tia [17]

{\Huge{\boxed{\mathbb{QUESTION}}}

Write three ratios equal to \frac{4}{36}

{\huge{\boxed{\mathbb{EXPLANATION\:WITH\:REASONING\;}}}

This ratio can be represented as 4:36

_______________________________

{\Huge{\boxed{\mathbb{THE\:RATIOS}}}

_______________________________

  • 1:9
  • 2:18
  • 3:27

_______________________________

{\huge{\boxed{\mathbb{TERMS}}}

Equivalent/Equal ratios<em> - Definition of Equivalent Ratio A ratio can be represented as a fraction. The concept of an equivalent ratio is similar to the concept of equivalent fractions. A ratio that we get either by multiplying or dividing by the same number, other than zero, to the antecedent and the consequent of a ratio is called an equivalent ratio.</em>

6 0
3 years ago
Suppose the number of children in a household has a binomial distribution with parameters n=12n=12 and p=50p=50%. Find the proba
nadya68 [22]

Answer:

a) 20.95% probability of a household having 2 or 5 children.

b) 7.29% probability of a household having 3 or fewer children.

c) 19.37% probability of a household having 8 or more children.

d) 19.37% probability of a household having fewer than 5 children.

e) 92.71% probability of a household having more than 3 children.

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem, we have that:

n = 12, p = 0.5

(a) 2 or 5 children

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{12,2}.(0.5)^{2}.(0.5)^{10} = 0.0161

P(X = 5) = C_{12,5}.(0.5)^{5}.(0.5)^{7} = 0.1934

p = P(X = 2) + P(X = 5) = 0.0161 + 0.1934 = 0.2095

20.95% probability of a household having 2 or 5 children.

(b) 3 or fewer children

P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{12,0}.(0.5)^{0}.(0.5)^{12} = 0.0002

P(X = 1) = C_{12,1}.(0.5)^{1}.(0.5)^{11} = 0.0029

P(X = 2) = C_{12,2}.(0.5)^{2}.(0.5)^{10} = 0.0161

P(X = 3) = C_{12,3}.(0.5)^{3}.(0.5)^{9} = 0.0537

P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0002 + 0.0029 + 0.0161 + 0.0537 = 0.0729

7.29% probability of a household having 3 or fewer children.

(c) 8 or more children

P(X \geq 8) = P(X = 8) + P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 8) = C_{12,8}.(0.5)^{8}.(0.5)^{4} = 0.1208

P(X = 9) = C_{12,9}.(0.5)^{9}.(0.5)^{3} = 0.0537

P(X = 10) = C_{12,10}.(0.5)^{10}.(0.5)^{2} = 0.0161

P(X = 11) = C_{12,11}.(0.5)^{11}.(0.5)^{1} = 0.0029

P(X = 12) = C_{12,12}.(0.5)^{12}.(0.5)^{0} = 0.0002

P(X \geq 8) = P(X = 8) + P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12) = 0.1208 + 0.0537 + 0.0161 + 0.0029 + 0.0002 = 0.1937

19.37% probability of a household having 8 or more children.

(d) fewer than 5 children

P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{12,0}.(0.5)^{0}.(0.5)^{12} = 0.0002

P(X = 1) = C_{12,1}.(0.5)^{1}.(0.5)^{11} = 0.0029

P(X = 2) = C_{12,2}.(0.5)^{2}.(0.5)^{10} = 0.0161

P(X = 3) = C_{12,3}.(0.5)^{3}.(0.5)^{9} = 0.0537

P(X = 4) = C_{12,4}.(0.5)^{4}.(0.5)^{8} = 0.1208

P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.0002 + 0.0029 + 0.0161 + 0.0537 + 0.1208 = 0.1937

19.37% probability of a household having fewer than 5 children.

(e) more than 3 children

Either a household has 3 or fewer children, or it has more than 3. The sum of these probabilities is 100%.

From b)

7.29% probability of a household having 3 or fewer children.

p + 7.29 = 100

p = 92.71

92.71% probability of a household having more than 3 children.

5 0
3 years ago
What is the value of |–3.25| ?
34kurt

<u>Answer:</u>

  • <em>3.25</em>

<u>Step-by-step explanation:</u>

<em>Rule: An absolute value will always be positive. </em>

<em>=> Referring to the rule, the absolute value of |–3.25| is 3.25.</em>

Hoped this helped.

BrainiacUser1357

3 0
3 years ago
Joey had 26 game cards. His friend Richard gave him some more, and now Joey has 100 cards. How many cards did Richard give to Jo
Roman55 [17]

Given:

Joey had 26 game cards.

His friend Richard gave him some more, and now Joey has 100 cards.

To find:

How many cards did Richard give to Joey?

Solution:

Let x be the number of cards that Richard give to Joey.

Joey had 26 game cards.

Now, the total cards joey has =26+x

Joey has total 100 cards.

26+x=100

x=100-26

x=74

Therefore, Richard gave him 74 cards.

3 0
3 years ago
Tim measures the length of four grasshoppers in his backyard: 5/4cm, 7/4cm, 9/4cm, 3/4cm. What is the average length?
hodyreva [135]

Answer:

1.5 cm

Step-by-step explanation:

To find averages, you add up all the values then divide by the amount of number there are (i.e, 6, 7, 8, so there would be three numbers and therefore divide by 3)

6 0
3 years ago
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