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m_a_m_a [10]
3 years ago
15

Kelly estimates it will take her 35 minutes to make the punch and 45 minutes to set up. Will Kelly finish before the guests arri

ve if she starts at 11:45 a.m? Explain your answer. (Kelly's guests will arrive at 1:30)
Mathematics
1 answer:
Semenov [28]3 years ago
3 0
Kelly will have enough time to finish before the guests arrive because 45+35 = 1 hour and 10 mins, which adds that with 11:45, it would be 12:55 when she finishes. Making it possible.
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tresset_1 [31]

Answer:

f(x) is y so the x=16 because 4*4=16

7 0
4 years ago
Help please!!!!!
Sergio [31]

Answer:

  • a. image 1

Step-by-step explanation:

<u>Given function:</u>

  • f(x) = 2*3ˣ

<u>Plot two points and check which graph has those:</u>

  • f(0) = 2*3⁰ = 2

and

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Points (0, 2) and (1, 6) are correct on the image 1 with blue graph

7 0
3 years ago
Can someone please help me with this question about given two points?Please help ASAP!!! :(
KonstantinChe [14]

Answer:

<em>The order of subtraction is not important in any of the coordinates</em>

Step-by-step explanation:

Distance Between Two Points

Given two points (x1,y2) (x2,y2), the distance between them is given by the formula

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

The difference between both coordinates is squared, then added, and finally extracted the square root.

Based on the principle that

a*a=a^2

and also

(-a)(-a)=a^2

We can notice it doesn't matter the sign of a the square of a is always positive. If we had subtracted in the opposite way, the distance would have resulted in exactly the same. In other words, the above formula is exactly the same as

d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}

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6 0
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zhenek [66]
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8 0
4 years ago
De moirve's <br> (√3-i ÷ √3+i)^6 = 1
bulgar [2K]

(√3 - <em>i </em>) / (√3 + <em>i</em> ) × (√3 - <em>i</em> ) / (√3 - <em>i</em> ) = (√3 - <em>i</em> )² / ((√3)² - <em>i</em> ²)

… = ((√3)² - 2√3 <em>i</em> + <em>i</em> ²) / (3 - <em>i</em> ²)

… = (3 - 2√3 <em>i</em> - 1) / (3 - (-1))

… = (2 - 2√3 <em>i</em> ) / 4

… = 1/2 - √3/2 <em>i</em>

… = √((1/2)² + (-√3/2)²) exp(<em>i</em> arctan((-√3/2)/(1/2))

… = exp(<em>i</em> arctan(-√3))

… = exp(-<em>i</em> arctan(√3))

… = exp(-<em>iπ</em>/3)

By DeMoivre's theorem,

[(√3 - <em>i </em>) / (√3 + <em>i</em> )]⁶ = exp(-6<em>iπ</em>/3) = exp(-2<em>iπ</em>) = 1

7 0
3 years ago
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