The answer is c. i hope i helped
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Hope this helps! :))
The value of cos(L) in the triangle is Five-thirteenths
<h3>What are right triangles?</h3>
Right triangles are triangles whose one of its angle has a measure of 90 degrees
<h3>How to determine the value of cos(L)?</h3>
The value of a cosine function is calculated as:
cos(L) = Adjacent/Hypotenuse
The hypotenuse is calculated as
Hypotenuse^2 = Opposite^2 + Adjacent^2
So, we have:
Hypotenuse^2 = 12^2 + 5^2
Evaluate
Hypotenuse^2 = 169
Take the square root of both sides
Hypotenuse = 13
So, we have
Adjacent = 5
Hypotenuse = 13
Recall that
cos(L) = Adjacent/Hypotenuse
This gives
cos(L) = 5/13
Hence, the value of cos(L) in the triangle is Five-thirteenths
Read more about right triangles at:
brainly.com/question/2437195
#SPJ1
It looks like you want to compute the double integral
over the region <em>D</em> with the unit circle <em>x</em> ² + <em>y</em> ² = 1 as its boundary.
Convert to polar coordinates, in which <em>D</em> is given by the set
<em>D</em> = {(<em>r</em>, <em>θ</em>) : 0 ≤ <em>r</em> ≤ 1 and 0 ≤ <em>θ</em> ≤ 2<em>π</em>}
and
<em>x</em> = <em>r</em> cos(<em>θ</em>)
<em>y</em> = <em>r</em> sin(<em>θ</em>)
d<em>x</em> d<em>y</em> = <em>r</em> d<em>r</em> d<em>θ</em>
Then the integral is
