The slope of a line usually determines id the line is negative or positive. For example, lines going uphill, or uphill slopes, are positive slopes. The slope will be a positive number such as, yet not limited to, 5, 10, or 57. Or you can also take their counter parts for example, downhill slopes would be considered negative slopes, meaning they go below zero, instead of above, like positive slopes. Hope this helps. :D
The original area of a face would be a^2. Now that you added b to the edge, the new area of each face would be (a+b)^2. To find how much the are increased, subtract a^2 from (a+b)^2.
So the answer is b(2a+b)
Solution:
we have been asked to verify that -5, 1/2, and 3/4 are the zeroes of the cubic polynomial 
To verify that whether the given values are zeros or not we will substitute the values in the given Polynomial, if it will returns zero, it mean that value is Zero of the polynomial. But if it return any thing other than zeros it mean that value is not the zero of the polynomial.
Let 



Hence -5, 1/2, and 3/4 are not the zeroes of the given Polynomial.
Since sum of roots
But 
Hence we do not find any relation between the coefficients and zeros.
Anyway if the given values doesn't represents the zeros then those given values will not have any relation with the coefficients of the p[polynomial.
Here it is given that AB || CD
< EIA = <GJB
Now
∠EIA ≅ ∠IKC and ∠GJB is ≅ ∠ JLD (Corresponding angles)
∠EIA ≅ ∠GJB then ∠IKC ≅ ∠ JLD (Substitution Property of Congruency)
∠IKL + ∠IKC 180° and ∠DLH + ∠JLD =180° (Linear Pair Theorem)
So
m∠IKL + m∠IKC = 180° ....(1)
But ∠IKC ≅ ∠JLD
m∠IKC = m∠JLD (SUBTRACTION PROPERTY OF CONGRUENCY)
So we have
m∠IKL + m∠JLD = 180°
∠IKL and ∠JLD are supplementary angles.
But ∠DLH and ∠JLD are supplementary angles.
∠IKL ≅ ∠DLH (CONGRUENT SUPPLEMENTS THEOREM)
Answer:
B
Step-by-step explanation:
like my answer please gimme the brain