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bulgar [2K]
3 years ago
14

a real estate broker sold your house for $72,00. the brokers commission was 6% of the selling pricw. how much would you get afte

r the commission price?
Mathematics
1 answer:
worty [1.4K]3 years ago
3 0
$72,00?

I'm assuming you are saying $7200, but if you are saying $72, just replace.

6% = 0.06

7200 / 0.06 = 432

So you would get $432. But trust me, no house is that cheap lol

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Find 19/25 of $25,000<br><br> A. $2,500<br> B.$15,000<br> C.$19,000<br> D.$1,900
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Which equation correctly applies the distributive property?
lesantik [10]

Answer: Option 'A' is correct.

Step-by-step explanation:

Since we have given that

Distributive law is defined as

a\times (b+c+d)=a\times b+a\times c+a\times d

According to option'A', we get that

a =- 3

b = 6

c = 0.4

d = 0.08

So, it becomes,

-3\times (6.48)=-3\times 6+(-3)\times 0.4+(-3)\times 0.08

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Distribution property 18+45
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3 years ago
Granola Crunch cereal is packaged in 1 pound boxes. Susan Torres, a quality control analyst who works for the manufacturer of th
sineoko [7]

Answer:

z=\frac{1.02-1}{\frac{0.04}{\sqrt{40}}}=3.162    

p_v =2*P(z>3.162)=0.0016    

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to to reject the null hypothesis, so we can conclude that the true mean is different from 1 pound at 5% of signficance.

Step-by-step explanation:

Data given and notation    

\bar X=1.02 represent the sample mean

\sigma=0.04 represent the population standard deviation    

n=40 sample size    

\mu_o =1 represent the value that we want to test  

\alpha=0.05 represent the significance level for the hypothesis test.    

z would represent the statistic (variable of interest)    

p_v represent the p value for the test (variable of interest)    

State the null and alternative hypotheses.    

We need to conduct a hypothesis in order to check if the true mean is equal to 1 pound or no :    

Null hypothesis:\mu =1    

Alternative hypothesis:\mu \neq 1    

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:    

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)    

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".    

Calculate the statistic    

We can replace in formula (1) the info given like this:    

z=\frac{1.02-1}{\frac{0.04}{\sqrt{40}}}=3.162    

P-value    

Since is a two-sided test the p value would be:    

p_v =2*P(z>3.162)=0.0016    

Conclusion    

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to to reject the null hypothesis, so we can conclude that the true mean is different from 1 pound at 5% of signficance.    

5 0
3 years ago
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