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nikdorinn [45]
3 years ago
5

PLEASE HELP PLEASE

Mathematics
1 answer:
SashulF [63]3 years ago
7 0

Answer: A

Step-by step explanation:

See paper attached. (:

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Solve for the missing length and the other two angles in the triangle below
Klio2033 [76]

Answer:

AC = 3.72 units

Angles:

A = 132.6°

C = 27.4°

Step-by-step explanation:

AC² = 5² + 8² - 2(5)(8)cos(20)

AC² = 13.82459034

AC = 3.718143399

3.718143399/sin20 = 8/sinA

sinA = 0.7358944647

A = 180 - 47.38285134

A = 132.6171487

3.718143399/sin20 = 5/sinC

sinC = 0.4599340405

C = 27.38285134

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3 years ago
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Write the equation of the line in fully simplified slope-intercept form.
Bad White [126]

Answer:

y = -\frac{2}{5} x-6

Step-by-step explanation:

1) First, find the slope of the line. Use the slope formula m =\frac{y_2-y_1}{x_2-x_1}. Pick two points on the line and substitute their x and y values into the formula, then solve. I used the points (-5,-4) and (0,-6):

m = \frac{(-6)-(-4)}{(0)-(-5)} \\m = \frac{-6+4}{0+5} \\m = \frac{-2}{5} \\  

So, the slope of the line is -\frac{2}{5}.

2) Next, use the point-slope formula y-y_1 = m (x-x_1) to write the equation of the line in point-slope form. (From there, we can convert it to slope-intercept form.) Substitute values for the m, x_1 and y_1 into the formula.

Since m represents the slope, substitute -\frac{2}{5}  in its place. Since x_1 and y_1 represent the x and y values of one point on the line, pick any point on the line (any one is fine, it will equal the same thing at the end) and substitute its x and y values in those places. (I chose (0,-6), as seen below.) Then, with the resulting equation, isolate y to put the equation in slope-intercept form:

y-(-6) = -\frac{2}{5} (x-(0))\\y + 6 = -\frac{2}{5} x\\y = -\frac{2}{5} x-6

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3 years ago
If the ordered pairs (x, -1) and (5, y) belong to the set {(a, b): b = 2a-3}, find x and y.​
Anika [276]
The ordered pair is 5x|x| ^2
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2 years ago
A Merit Rating System for SUTA means:
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