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3 years ago

I need a lil help, ANSWER QUICKLY!

Mathematics

2 answers:

Valentin [98]3 years ago

7 0

Answer:

yes

Step-by-step explanation:

Counterclockwise is going left, so if you start at the top, 270 degrees left of a clock will result in the same as 90 degrees clockwise.

Leno4ka [110]3 years ago

4 0

Answer:

Yes it will.

Step-by-step explanation:

Imagine a circle. A full rotation is 360 degrees. So, that means you're going to be 90 degrees froma full rotation. That means that if you back track 90 degrees you're going to get to the same spot as when you go clockwise 270 degrees. The best way to think of it is having the hands of a clock start at 12.

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What is 10 more than 451

snow_lady [41]

To find 10 more than 451 is very simple, simply add 10 to 451 to get 461.

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3 years ago

Square GYTD has vertices G(−4,3) , Y(0, 3) , T(0,−1) and D(−4,−1) . Square GYTD is translated 2 units left and 2 units up to

Sliva [168]

we know that

If square GYTD is translated $2$ units left and $2$ units up to produce square G'Y'T'D'

that means

the rule of transformation is

$(x,y)-------> (x-2,y+2)$

Find the coordinates of the image

$G (-4,3)------->G'(-4-2,3+2)=G'(-6,5)$

$Y (0,3)------->Y'(0-2,3+2)=Y'(-2,5)$

$T (0,-1)------->T'(0-2,-1+2)=T'(-2,1)$

$D (-4,-1)------->D'(-4-2,-1+2)=D'(-6,1)$

therefore

the answer is the option

G'(−6, 5), Y'(−2, 5), T'(−2, 1) , and D′(−6, 1)

6 0

3 years ago

Read 2 more answers

Triangle

sertanlavr [38]

Answer:

Step-by-step explanation:

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6 0

3 years ago

Suppose we have an urn containing 9 marbles. Two are red, three are green, and four are blue. We randomly select 5 marbles from

Aleonysh [2.5K]

Answer:

probability of selecting 3 green marbles, 1 red marble, and 1 blue marbles

$P(E) =\frac{8}{126} = 0.0634$

Step-by-step explanation:

Given data urn containing '9' marbles

given red marbles = 2

green marbles =3

blue marbles = 4

Five marbles can be selected at a time from '9' marbles in $9_{C_{5} }$ ways

by using formula $n_{C_{r} }=\frac{n!}{(n-r)!r!}$

$9_{C_{5} }=\frac{9!}{(9-5)!5!} = \frac{9X8X7X6X5!}{4!5!}$

After simplification , we get $9_{C_{5} } = 126$

total number of ways n(S) = 126

The probability of selecting '3' green marbles ,one red marble and one blue marble with replacement.

let ' E' be the event of selecting '3' green marbles ,one red marble and one blue marble with replacement.

n(E) = $3_{C_{3} } X2_{C_{1} }X 4_{C_{1} }$ ways

The required probability $P(E) = \frac{n(E)}{n(S)}$

$p(E) = \frac{3_{C_{3} } X2_{C_{1} }X 4_{C_{1} }}{9_{C_{5} } }$

on simplification , we get

$P(E) = \frac{1X2X4}{126} =\frac{8}{126}$

$P(E) =\frac{8}{126} = 0.0634$

7 0

3 years ago

Please help me time test that is due today!!!!!!

Anna007 [38]

Answer:

Step-by-step explanation:

OK, they ask how many student like snowmobile and do not like skate board, so go to vertical side on the left, pick like snowmobile, look across the chart, look at do not like skateboards, It says 25. That is your answer!

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2 years ago