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o-na [289]
3 years ago
8

A moving company has one large truck for furniture and one small truck for boxes. During one move, it took the large truck 4 hou

rs to travel 180 miles. It took the small truck 3 hours to make the same trip. Assume both trucks traveled at constant speeds. How fast did each truck travel?
Mathematics
1 answer:
s2008m [1.1K]3 years ago
4 0

Answer:

large truck = 45miles small truck = 60miles

Step-by-step explanation:

180/4 and 180/3

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Vlad1618 [11]
<span>There are several ways to do this problem. One of them is to realize that there's only 14 possible calendars for any year (a year may start on any of 7 days, and a year may be either a leap year, or a non-leap year. So 7*2 = 14 possible calendars for any year). And since there's only 14 different possibilities, it's quite easy to perform an exhaustive search to prove that any year has between 1 and 3 Friday the 13ths. Let's first deal with non-leap years. Initially, I'll determine what day of the week the 13th falls for each month for a year that starts on Sunday. Jan - Friday Feb - Monday Mar - Monday Apr - Thursday May - Saturday Jun - Tuesday Jul - Thursday Aug - Sunday Sep - Wednesday Oct - Friday Nov - Monday Dec - Wednesday Now let's count how many times for each weekday, the 13th falls there. Sunday - 1 Monday - 3 Tuesday - 1 Wednesday - 2 Thursday - 2 Friday - 2 Saturday - 1 The key thing to notice is that there is that the number of times the 13th falls upon a weekday is always in the range of 1 to 3 days. And if the non-leap year were to start on any other day of the week, the numbers would simply rotate to the next days. The above list is generated for a year where January 1st falls on a Sunday. If instead it were to fall on a Monday, then the value above for Sunday would be the value for Monday. The value above for Monday would be the value for Tuesday, etc. So we've handled all possible non-leap years. Let's do that again for a leap year starting on a Sunday. We get: Jan - Friday Feb - Monday Mar - Tuesday Apr - Friday May - Sunday Jun - Wednesday Jul - Friday Aug - Monday Sep - Thursday Oct - Saturday Nov - Tuesday Dec - Thursday And the weekday totals are: Sunday - 1 Monday - 2 Tuesday - 2 Wednesday - 1 Thursday - 2 Friday - 3 Saturday - 1 And once again, for every weekday, the total is between 1 and 3. And the same argument applies for every leap year. And since we've covered both leap and non-leap years. Then we've demonstrated that for every possible year, Friday the 13th will happen at least once, and no more than 3 times.</span>
5 0
3 years ago
The square root of 27 lies between which two whole numbers
Agata [3.3K]

Answer:

5 and 6

Step-by-step explanation:

The square root of 27 is 5.19615242271  , which is more than 5 but less then 6, therefore is between 5 and 6.

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<em>Hope this helped (: Can you please mark as brainliest?</em>

7 0
3 years ago
Which equation represents a line that passes through (4, left-parenthesis 4, StartFraction one-third EndFraction right-parenthes
Alina [70]

Answer:

y-\frac{1}{3}=\frac{3}{4}(x-4)

Step-by-step explanation:

we know that

The equation of the line into point slope form is equal to

y-y1=m(x-x1)

In this problem we have

point\ (4,\frac{1}{3})

m=\frac{3}{4}

substitute the given values

y-\frac{1}{3}=\frac{3}{4}(x-4)

y minus StartFraction one-third EndFraction equals StartFraction 3 Over 4 EndFraction left-parenthesis x minus 4 right-parenthesis.(x – 4)

7 0
3 years ago
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iVinArrow [24]
The answer is D because the function is a cubic function. if you graph for example, x³, it would be in Q. 1 and 3
5 0
4 years ago
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Two cards are drawn without replacement from a standard deck of 52 playing cards. What is the probability of choosing a red card
joja [24]

Answer: \dfrac{3}{51}

Step-by-step explanation:

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\dfrac{12}{51}

Now, the probability of choosing a red card for the second card drawn, if the first card, drawn without replacement, was a diamond :-

\dfrac{1}{4}\times\dfrac{12}{51}=\dfrac{3}{51}

7 0
3 years ago
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