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Scrat [10]
3 years ago
12

A point has zero dimension. True or False?

Mathematics
2 answers:
djverab [1.8K]3 years ago
7 0

Answer:

True

Step-by-step explanation:

A point is zero-dimensional with respect to the covering dimension because every open cover of the space has a refinement consisting of a single open set.

Dominik [7]3 years ago
6 0

Answer: Its true that a point has zero dimensions

Step-by-step explanation:

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The sum of an even number and odd number is always even
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Yes your correct but thats not a question
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Choose the correct description of the graph of the inequality x - 3s 5.
padilas [110]

Answer:

x - 3 > = 5

x > = 5 + 3

x > = 8

closed circle on 8...because of the equal sign.....shaded to the right...because of the > sign.

Step-by-step explanation:

6 0
3 years ago
Find the surface area of the regular pyramid
kicyunya [14]

Pyramid Surface Area = (½ * Perimeter of Base * Slant Height) + Base Area

Pyramid Surface Area = (.5 * 56 * 11) + 14 * 14Pyramid Surface Area = 308 + 196Pyramid Surface Area =504 square millimeters

Source:http://www.1728.org/volpyrmd.htm

5 0
3 years ago
You could win a giant jar of M&Ms, if only you could guess how many are in the jar. You find a smallerjar such that the gian
sleet_krkn [62]

Answer:

There are 7360 M&Ms in larger jar.

Step-by-step explanation:

We are given the following in the question:

A giant jar is such that it is exactly four times times the smaller jar in dimensions.

If r and h is the radius and height of the cylindrical jar respectively, then the dimensions of the larger are:

R = 4r\\H=4h

Number of M&Ms in smaller jar = 115

Volume of smaller jar =

v = \dfrac{1}{3}\pi r^2 h

Volume of larger jar =

V =\dfrac{1}{3}\pi R^2 H=\dfrac{64}{3}\pi r^2 h

Number of M&Ms in larger jar:

v = \dfrac{1}{3}\pi r^2 h\rightarrow 115\\\\V=\dfrac{64}{3}\pi r^2 h\rightarrow 115\times 64\\\\V=\dfrac{64}{3}\pi r^2 h\rightarrow 7360

Thus, there are 7360 M&Ms in larger jar.

6 0
3 years ago
Answer all..............
Snowcat [4.5K]

A)

3 -  \frac{2}{3}  =  2 \frac{1}{3}

B)

4 +  \frac{2}{5}  = 4 \frac{2}{5}

C)

5 \div  \frac{4}{7}  = 8  \frac{3}{4}

D)

\frac{4}{5}  \times \frac{2}{3 }   =  \frac{8}{15}

e)

\frac{1}{3}  \div  \frac{3}{5}  =  \frac{5}{9}

7 0
2 years ago
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