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siniylev [52]
3 years ago
10

The typical full-time employee in a particular hotel works a 40-hour week. Last month, the hotel's 80 employees worked a total o

f 4,000 hours. How many full-time equivalent (FTE) workers were employed by the hotel last month?
Mathematics
1 answer:
Mila [183]3 years ago
7 0

Answer: There are 25 FTEs.

Step-by-step explanation:

Since we have given that

Number of hour week for full time employee = 40 hours

In a month we know that

Number of weeks = 4

Total number of hours in a month would be

40\times 4\\\\=160\ hours

If in last month, the hotel's 80 employees worked a total of 4000 hours,

So, Full time equivalent workers were employed by the hotel last month would be

\dfrac{4000}{160}\\\\=25

Hence, there are 25 FTEs.

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Studentka2010 [4]

Answer:

Those functions are for a graph.

Step-by-step explanation:

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These are functions that can be graphed, I assume you know what that is, if not, look it up.

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Use Order of Operations to simplify. 42 – (28 ÷ 7) + 111
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I don’t really get this one.<br> Thx and have a great day!!
gayaneshka [121]

Answer:

The correct option is C). (9,4)

The coordinates of a point N is (9,4)

Step-by-step explanation:

Theory: If point P(x,y) lies on line segment AB and AP: PB=m:n, then we say P divides line AB internally in ratio of m:n and Point is given by

P=(\frac{mX2+nX1}{m+n} , \frac{mY2+nY1}{m+n})

Given that point, M is lying somewhere between point L and point N.

The coordinates of a point L is (-6,14)

The coordinates of a point M is (-3,12)

Also, LM: MN = 1:4

We can write as,

Let,

Point L(-6,14)=(X1, Y1)

Point M(-3,12)=(x,y)

Point N is (X2, Y2)

m=1 and n=4

M(-3,12)=(\frac{mX2+nX1}{m+n} , \frac{mY2+nY1}{m+n})

M(-3,12)=(\frac{1(X2)+4(-6)}{1+4} , \frac{(Y2)+4(14)}{1+4})

M(-3,12)=(\frac{(X2)-24}{5} , \frac{1(Y2)+56}{5})

(-3)=\frac{(X2)-24}{5}

(-15)=X2-24

X2=9

(12)=\frac{(Y2)+56}{5}

(60)=Y2+56

Y2=4

Thus,

The coordinates of a point N is (9,4)

Result: The correct option is C). (9,4)

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