The value of g after solving the expression, 5/2-2g = 5g/2-3+g, is 1.
According to the question,
We have the following expression:
5/2-2g = 5g/2-3+g
Now, moving the terms with the same variables on one side and the integers on another side.
Note that when we move any number of term from one side to another which is in addition or subtraction will result in change of the sign from minus to plus and plus to minus.
5/2+3 = 2g+5g/2+g
Taking 2 as the least common factor on the left hand side and right hand side:
(5+6)/2 = (4g+2g+5g)/2
11/2 = 11g/2
Now, 11/2 on the left hand side can be divided by 11/2 on the right hand side:
g = 1
Hence, the value of g is 1.
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Answer:
12 girls
28 boys
Step-by-step explanation:
Multiply 40 by 30/100 to get 12 girls.
Subtract 12 from 40 to get 28 boys.
Answer:
a) mean = 0.125, standard deviation = 0.1397
b)0.1867
c) 0.1867
Step-by-step explanation:
The width of a casing for a door is normally distributed with a mean of 24 inches and a standard deviation of 1/8 inch. The width of a door is normally distributed with a mean of 23 7/8 inches and a standard deviation of 1/16 inch. Assume independence. a. Determine the mean and standard deviation of the difference between the width of the casing and the width of the door. b. What is the probability that the width of the casing minus the width of the door exceeds 1/4 inch? c. What is the probability that the door does not fit in the casing?
Let X denote width of a casing for a door and Y be width of a door.If X and Y is normally distributed, X → N(u, σ²) = N(24, (1/8)²)
Also Y → N(u, σ²) = N(23.875, (1/16)²)
a) Let T be the random variable that denote the difference between width of a casing for a door and width of a door. T = X - Y
E(T) = E(X) - E(Y) = 24 - 23.875 = 0.125
V(T) = V(X) + V(Y) = (1/8)² + (1/16)² = 0.01953
σ(T) = √V(T) = 0.1397
Therefore T → N(u, σ²) = N(0.125, 0.01953)
b) P(T > 0.25)
Using Z score,
P(T > 0.25) = P(Z > 0.89) = 1 - P(Z<0.89) = 1 - 0.8133= 0.1867
c) P(T < 0)
Using Z score,
P(T < 0) = P(Z < -0.89) = 0.1867
Hello, if "3" your 'underlined digit" then you're answer would be: the 3 is in the "tens " place
Good luck!