All categories

3 years ago

Between what two integers does 98 fall between

Mathematics

1 answer:

Nat2105 [25]3 years ago

8 0

Answer: 99 and 97

Step-by-step explanation: If you make a numberline and write the numbers 90 through 100. 98 is in between integers 99 and 97.

You might be interested in

Can someone complete the square

pshichka [43]

To do these, start by looking at the "b" value -6.
divide it by 2

-6/2 = -3

now square this number

(-3)^2 = 9

this is what you need for the "c" value

there is only a 5 for the c value so add 4 to both sides of the equation. ( +4 = +4)

y +4 = x^2 -6x +5 +4
y +4 = x^2 -6x +9
y +4 = (x -3)^2
y = (x -3)^2 - 4

vertex ( 3, -4) upwards facing like a bowl, because the "a" value is positive. So the vertex is the minimum, lowest point on the graph.

7 0

3 years ago

7x+2y=-28<br><br><br>Help write slope-intercept form pls

kap26 [50]

Answer:

y = - $\frac{7}{2}$ x - 14

Step-by-step explanation:

Slope intercept form: y = mx + b

Isolate the y:

7x + 2y = -28

2y = -7x - 28

y = - $\frac{7}{2}$ x - 14

3 0

3 years ago

Mr.sanchez drives 120 miles in 3 hours. At the same rate, how far will he drive in 5 hours

Rina8888 [55]

To elaborate:

To do this problem, we assume that Mr. Sanchez is driving at a constant rate.

According to this information, he has driven 120 mi in 3 hr. To find how much he drives in 5 hr, we first have to find how many mi he drives in 1 hour. To do this, we divide 120 miles by 3 hours, since we assume that he managed to drive an equal amount in each hour.

120/3=40

Therefore Mr. Sanchez drove at a rate of 40 mph.

However, this isn't the final answer. 40 miles is the distance for one hour of driving. To find the distance for 5 hours, we have to multiply the distance by 5 as well.

40 times 5=200

In conclusion, Mr. Sanchez will drive 200 miles in 5 hours.

4 0

3 years ago

Read 2 more answers

A college student is taking two courses. The probability she passes the first course is 0.73. The probability she passes the sec

zhenek [66]

Answer:

b) No, it's not independent.

c) 0.02

d) 0.59

e) 0.57

f) 0.5616

Step-by-step explanation:

To answer this problem, a Venn diagram should be useful. The diagram with the information of Event 1 and Event 2 is shown below (I already added the information for the intersection but we're going to see how to get that information in the b) part of the problem)

Let's call A the event that she passes the first course, then P(A)=.73

Let's call B the event that she passes the second course, then P(B)=.66

Then P(A∪B) is the probability that she passes the first or the second course (at least one of them) is the given probability. P(A∪B)=.98

b) Is the event she passes one course independent of the event that she passes the other course?

Two events are independent when P(A∩B) = P(A) * P(B)

So far, we don't know P(A∩B), but we do know that for all events, the next formula is true:

P(A∪B) = P(A) + P(B) - P(A∩B)

We are going to solve for P (A∩B)

.98 = .73 + .66 - P(A∩B)

P(A∩B) =.73 + .66 - .98

P(A∩B) = .41

Now we will see if the formula for independent events is true

P(A∩B) = P(A) x P(B)

.41 = .73 x .66

.41 ≠.4818

Therefore, these two events are not independent.

c) The probability she does not pass either course, is 1 - the probability that she passes either one of the courses (P(A∪B) = .98)

1 - P(A∪B) = 1 - .98 = .02

d) The probability she doesn't pass both courses is 1 - the probability that she passes both of the courses P(A∩B)

1 - P(A∩B) = 1 -.41 = .59

e) The probability she passes exactly one course would be the probability that she passes either course minus the probability that she passes both courses.

P(A∪B) - P(A∩B) = .98 - .41 = .57

f) Given that she passes the first course, the probability she passes the second would be a conditional probability P(B|A)

P(B|A) = P(A∩B) / P(A)

P(B|A) = .41 / .73 = .5616

4 0

3 years ago

Witch is grater 3/4 or 11/16 ??

kow [346]

<h3>Hey there! </h3><h3> $\frac{3}{4}$ → $0.75$ → $0.75$ %</h3><h3> $\frac{11}{16}$ → $0.6875$ → $0.68$ % </h3><h3>So, the one that is $GREATER$ is: $\frac{3}{4}$ because $75$ % is bigger than</h3><h3> $68$ %</h3><h3>Good luck on your assignment and enjoy your day! </h3><h3>~ $LoveYourselfFirst:)$ </h3>

5 0

3 years ago