Let X be chickens
Let Y be pigs,
then x+y=13
the animals have 2x+4y legs,
so 2x+4y=40
The system of the equations
[X+y=13
[2x+4y=40
Divide the second equation by 2
[x+y=13
[x+2y=20
subtract the first equation from the second one
y=20-13
y-7 pigs
substitute y=7 into the first equation
x+7=13
x=13-7
x=6 chickens
There are only two numbers that are 10 away from 0 it would be 10 and -10
Answer:
Values for x = -1 + 7i and -1 - 7i
Step-by-step explanation:
we have an equation,
(x+1)^2 = -49
We need to solve this equation for all values of x:
(x+1)^2 = - 49
Taking square root both sides
√((x +1)^2) = √-49
x + 1 = ± 7i
Subtract both sides by 1
x = -1 ± 7i
Hence we get two values for x = -1 + 7i and -1 - 7i
1.) no
2.)no
3.)no
4.)no
5.)no
6.)no
7.)no
8.)no
He will receive $13.70.
You would have to multiply 2.25 by 2.80 to get 6.30, which is the total cost due. Subtract 6.30 from 20 to get your answer, 13.70, or the change Mr. Stein will receive.
