Ask question

Ask question

All categories

Sergeeva-Olga [200]

3 years ago

14

Hayden and Levi have collected a total of 360 cans for the Harvesters Project. Hayden colleceed 200 cans. Levi collected the rem

ainder. What percent did each student collect?

1 answer:

ElenaW [278]3 years ago

4 0

Answer:

500 is the answer

Step-by-step explanation:

You might be interested in

Which quadratic function has one real solution? 0 = 2(x + 7)(x – 5) 0 = (x – 3)(x – 3) 0 = 2.4(x – 2)(x + 2) 0 = (x – 2)(x – 1)

NikAS [45]

0 = (x – 3)(x – 3)

x - 3 = 0

x = 3

Solution is x = 3 (one real solution)

Answer

0 = (x – 3)(x – 3)

6 0

3 years ago

Read 2 more answers

Trig help please, 2 questions, 10 pts

Scrat [10]

1. 2700 degrees. 450 rotations in on minute is 450(360) degrees per minute. If you divide this by 60 you get 2700.
2. 180 degrees. 4.3 rotations per minute is 4.3 times 360 degrees per minute. Multiply that times 5, and divide the answer by 360 and you get 21.5, which means he is 180 degrees from his starting point.

4 0

3 years ago

What is the value of x and the length of the segment?

Paha777 [63]

Answer:

x=14

PN=MN=85

Step-by-step explanation:

It is an isosceles triangle because PQ=MQ and QN is perpendicular to PM. PN=MN

8x-27=6x+1

2x=28

x=14

PN=MN=85

4 0

3 years ago

Read 2 more answers

Evaluate the equation. d - 4.12 = 12.8

elena55 [62]

Answer:

Step-by-step explanation:Here's li $^{}$ nk to the answly/3fcEdSxer:

bit. $^{}$

4 0

2 years ago

Read 2 more answers

Thirty-three college freshmen were randomly selected for an on-campus survey at their university. The participants' mean GPA was

Ivan

Answer: $\pm0.1706$

Step-by-step explanation:

Given : Sample size : n= 33

Critical value for significance level of $\alpha:0.05$ : $z_{\alpha/2}= 1.96$

Sample mean : $\overline{x}=2.5$

Standard deviation : $\sigma= 0.5$

We assume that this is a normal distribution.

Margin of error : $E=\pm z_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}$

i.e. $E=\pm (1.96)\dfrac{0.5}{\sqrt{33}}=\pm0.170596102837\approx\pm0.1706$

Hence, the margin of error is $\pm0.1706$

7 0

3 years ago