Show that AC and BD bisect each other if A(–3, –5), B(2, –3), C(3, 5), and D(–2, 3). Find AC and BD

Mathematics

2 answers:

Mazyrski [523]3 years ago

7 0

Answer

Multipy all of them

Step-by-step explanation:

mulitiply all of them

Mashcka [7]3 years ago

3 0

Answer:

Step-by-step explanation:

midpoint of AC=((-3+3)/2,(-5+5)/2)=(0,0)

midpoint of BD=((2-2)/0,(-3+3)/2)=(0,0)

coordinates of midpoint of AC and BD are same.

∴ AC and BD bisect each other.

$AC=\sqrt{(3-(-3))^2+(5-(-5))^2 } =\sqrt{6^2+10^2} =\sqrt{136} =2\sqrt{39} \\BD=\sqrt{((-2-2)^2+(3-(-3))^2} =\sqrt{16+36} =\sqrt{52} =2\sqrt{13}$

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balandron [24]

Answer:

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Step-by-step explanation:

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<h3><u>Averages</u></h3>

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