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Natalija [7]
3 years ago
6

Show that AC and BD bisect each other if A(–3, –5), B(2, –3), C(3, 5), and D(–2, 3). Find AC and BD

Mathematics
2 answers:
Mazyrski [523]3 years ago
7 0

Answer

Multipy all of them

Step-by-step explanation:

mulitiply all of them

Mashcka [7]3 years ago
3 0

Answer:

Step-by-step explanation:

midpoint of AC=((-3+3)/2,(-5+5)/2)=(0,0)

midpoint of BD=((2-2)/0,(-3+3)/2)=(0,0)

coordinates  of midpoint of AC and BD are same.

∴ AC and BD bisect each other.

AC=\sqrt{(3-(-3))^2+(5-(-5))^2 } =\sqrt{6^2+10^2} =\sqrt{136} =2\sqrt{39} \\BD=\sqrt{((-2-2)^2+(3-(-3))^2} =\sqrt{16+36} =\sqrt{52} =2\sqrt{13}

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2 years ago
The figure shows a triangle with its three angle bisectors intersecting at Point P.
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Check the picture below.

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2 years ago
I need help solving this problem with proofs if at all possible
k0ka [10]

I don't really like these algebra problems which pretend to be geometry.

The bisector makes two equal angles, so

x/2 + 17 = x - 33

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That means ABC = 100/2 + 17 = 67 degrees

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4 0
3 years ago
Read 2 more answers
Please help this is my 3rd time asking :(​
Ainat [17]

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$6

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2 years ago
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If f(x) = -7x + 1 and g(x) = Square root of x-5,<br> what is (fºg)(41)?
Ghella [55]

This is similar to the other question you posted. Follow the same steps as before.

First find g(41).

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Answer:

(fºg)(41) = -41

Did you follow?

6 0
2 years ago
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