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son4ous [18]
3 years ago
14

Solve for t: t ÷ 5 = 8

Mathematics
1 answer:
DIA [1.3K]3 years ago
8 0

Answer:

Step-by-step explanation:

Equation is t÷5=8

first you multiply 5 on each to cancel it out

t÷5*5=8*5

solve to get

t=40

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Add. write your answer as a mixed number in simplest form. 5 1/2+6 7/9
LiRa [457]
The answer is 12 5/18 hope it helps
7 0
3 years ago
Standard Error from a Formula and a Bootstrap Distribution Sample A has a count of 30 successes with and Sample B has a count of
tia_tia [17]

Answer:

Using a formula, the standard error is: 0.052

Using bootstrap, the standard error is: 0.050

Comparison:

The calculated standard error using the formula is greater than the standard error using bootstrap

Step-by-step explanation:

Given

Sample A                          Sample B

x_A = 30                              x_B = 50

n_A = 100                             n_B =250

Solving (a): Standard error using formula

First, calculate the proportion of A

p_A = \frac{x_A}{n_A}

p_A = \frac{30}{100}

p_A = 0.30

The proportion of B

p_B = \frac{x_B}{n_B}

p_B = \frac{50}{250}

p_B = 0.20

The standard error is:

SE_{p_A-p_B} = \sqrt{\frac{p_A * (1 - p_A)}{n_A} + \frac{p_A * (1 - p_B)}{n_B}}

SE_{p_A-p_B} = \sqrt{\frac{0.30 * (1 - 0.30)}{100} + \frac{0.20* (1 - 0.20)}{250}}

SE_{p_A-p_B} = \sqrt{\frac{0.30 * 0.70}{100} + \frac{0.20* 0.80}{250}}

SE_{p_A-p_B} = \sqrt{\frac{0.21}{100} + \frac{0.16}{250}}

SE_{p_A-p_B} = \sqrt{0.0021+ 0.00064}

SE_{p_A-p_B} = \sqrt{0.00274}

SE_{p_A-p_B} = 0.052

Solving (a): Standard error using bootstrapping.

Following the below steps.

  • Open Statkey
  • Under Randomization Hypothesis Tests, select Test for Difference in Proportions
  • Click on Edit data, enter the appropriate data
  • Click on ok to generate samples
  • Click on Generate 1000 samples ---- <em>see attachment for the generated data</em>

From the randomization sample, we have:

Sample A                          Sample B

x_A = 23                              x_B = 57

n_A = 100                             n_B =250

p_A = 0.230                          p_A = 0.228

So, we have:

SE_{p_A-p_B} = \sqrt{\frac{p_A * (1 - p_A)}{n_A} + \frac{p_A * (1 - p_B)}{n_B}}

SE_{p_A-p_B} = \sqrt{\frac{0.23 * (1 - 0.23)}{100} + \frac{0.228* (1 - 0.228)}{250}}

SE_{p_A-p_B} = \sqrt{\frac{0.1771}{100} + \frac{0.176016}{250}}

SE_{p_A-p_B} = \sqrt{0.001771 + 0.000704064}

SE_{p_A-p_B} = \sqrt{0.002475064}

SE_{p_A-p_B} = 0.050

5 0
3 years ago
What is 2+4/5x15-190?
aleksley [76]

Answer:

- 176

Step-by-step explanation:

2 + 4/5 x 15 - 190

= 2 + (4/5 x 15) - 190

= 2 + (12) - 190

= 2 + 12 - 190

= 14 - 190

= - 176

5 0
3 years ago
Read 2 more answers
Cual es la amplitud de estos conjuntos de datos 12,16,48,64,36,48,12,32,y 48
nalin [4]
Answer:









Step-by-step explanation:
8 0
3 years ago
One out of 23 high school ball players plays college ball. One out of 35 college players plays professional ball. What fraction
Gnoma [55]

Answer:

\frac{35}{23} is the required fraction.

Step-by-step explanation:

We have  been given  that  23 high school ball players plays college ball.

And 35 college players plays professional ball  

So we need to find fraction of high school players professional ball

\frac{35}{23} is the required fraction.


6 0
3 years ago
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