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3 years ago

Solve for t: t ÷ 5 = 8

Mathematics

1 answer:

DIA [1.3K]3 years ago

8 0

Answer:

Step-by-step explanation:

Equation is t÷5=8

first you multiply 5 on each to cancel it out

t÷5*5=8*5

solve to get

t=40

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A frozen dinner is divided into 3 sections on a circular plate with a 12-inch diameter. The central angle formed by the peach co

Vsevolod [243]

Answer:

D. 5 inches

Step-by-step explanation:

Given:

A frozen dinner is divided into 3 sections on a circular plate with a 12-inch diameter.

That means complete angle having 360° is divided into 3 section.

The central angle formed by the peach cobbler is 105 degrees.

The central angle formed by the pasta is 203 degrees.

Question asked:

What is the approximate length of the arc of the section containing the peas?

Solution:

The central angle formed by the peas = 360° - 105° - 203°

= 52°

$Ridius,r=\frac{Dameter}{2} =\frac{12}{2} =6\ inches$

As we know:

$Length\ of\ arc=2\pi r\times\frac{\Theta }{360}$

$=2\times\frac{22}{7} \times6\times\frac{52}{360} \\ \\ =\frac{13728}{2520} \\ \\ =5.44\ inches$

Therefore, the approximate length of the arc of the section containing the peas are 5 inches.

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3 years ago

Does this equation describe a linear function? y = 2/X - 29

cupoosta [38]

Answeryes

Step-by-step explanation:

5 0

3 years ago

A circle has the order pairs (-1, 2) (0, 1) (-2, -1) what is the equation . Show your work.

olga55 [171]

We know that:

$(x-a)^2+(y-b)^2=r^2$

is an equation of a circle.

When we substitute x and y (from the pairs we have), we'll get a system of equations:

$\begin{cases}(-1-a)^2+(2-b)^2=r^2\\(0-a)^2+(1-b)^2=r^2\\(-2-a)^2+(-1-b)^2=r^2\end{cases}$

and all we have to do is solve it for a, b and r.

There will be:

$\begin{cases}(-1-a)^2+(2-b)^2=r^2\\(0-a)^2+(1-b)^2=r^2\\(-2-a)^2+(-1-b)^2=r^2\end{cases}\\\\\\
\begin{cases}1+2a+a^2+4-4b+b^2=r^2\\a^2+1-2b+b^2=r^2\\4+4a+a^2+1+2b+b^2=r^2\end{cases}\\\\\\
\begin{cases}a^2+b^2+2a-4b+5=r^2\\a^2+b^2-2b+1=r^2\\a^2+b^2+4a+2b+5=r^2\end{cases}\\\\\\
$

From equations (II) and (III) we have:

$\begin{cases}a^2+b^2-2b+1=r^2\\a^2+b^2+4a+2b+5=r^2\end{cases}\\--------------(-)\\\\a^2+b^2-2b+1-a^2-b^2-4a-2b-5=r^2-r^2\\\\-4a-4b-4=0\qquad|:(-4)\\\\\boxed{-a-b-1=0}$

and from (I) and (II):

$\begin{cases}a^2+b^2+2a-4b+5=r^2\\a^2+b^2-2b+1=r^2\end{cases}\\--------------(-)\\\\a^2+b^2+2a-4b+5-a^2-b^2+2b-1=r^2-r^2\\\\2a-2b+4=0\qquad|:2\\\\\boxed{a-b+2=0}$

Now we can easly calculate a and b:

$\begin{cases}-a-b-1=0\\a-b+2=0\end{cases}\\--------(+)\\\\-a-b-1+a-b+2=0+0\\\\-2b+1=0\\\\-2b=-1\qquad|:(-2)\\\\\boxed{b=\frac{1}{2}}\\\\\\\\a-b+2=0\\\\\\a-\dfrac{1}{2}+2=0\\\\\\a+\dfrac{3}{2}=0\\\\\\\boxed{a=-\frac{3}{2}}$

Finally we calculate $r^2$ :

$a^2+b^2-2b+1=r^2\\\\\\\left(-\dfrac{3}{2}\right)^2+\left(\dfrac{1}{2}\right)^2-2\cdot\dfrac{1}{2}+1=r^2\\\\\\\dfrac{9}{4}+\dfrac{1}{4}-1+1=r^2\\\\\\\dfrac{10}{4}=r^2\\\\\\\boxed{r^2=\frac{5}{2}}$

And the equation of the circle is:

$(x-a)^2+(y-b)^2=r^2\\\\\\\left(x-\left(-\dfrac{3}{2}\right)\right)^2+\left(y-\dfrac{1}{2}\right)^2=\dfrac{5}{2}\\\\\\\boxed{\left(x+\dfrac{3}{2}\right)^2+\left(y-\dfrac{1}{2}\right)^2=\dfrac{5}{2}}$

7 0

3 years ago

Give a decimal number that is less than 23.7 and greater than 23.7

Makovka662 [10]

I think you are asking for two numbers, so you just have to look at the decimals.

23.7

We can use an infinite amount of numbers here, but to make it simple you can just take away 0.01 or add 0.01.

23.69
23.71

These are funny answers as well because they both round to 23.7 and meet the requirements.

3 0

3 years ago

Read 2 more answers

What is the product when 20 3 is multiplied with 9 25 ?

Novay_Z [31]

Answer:

187.775

Step-by-step explanation:

20.3×9.25=

187.775

4 0

2 years ago