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sashaice [31]
3 years ago
7

As an unenrolled tax preparer, Daryl is subject to:

Mathematics
2 answers:
-BARSIC- [3]3 years ago
3 0
I think there are missing details in this question. I'll just discuss what an unenrolled tax preparer is.

Unenrolled Tax Preparers are individuals who <span>possess the minimum qualifications required to prepare federal taxes and are granted a Preparer Tax Identification Number (PTIN) but are not Certified Public Accountants (CPA), lawyers, or enrolled agents.

They are only limited to filing only certain types of tax returns and can only represent their client on the basic audit level before the IRS. 

In order for an unenrolled tax preparer to become an enrolled agent, he or she must do the following:
1) Pass a three-part examination before the IRS 
2) Undergo compliance check on their tax history
3) Complete 16 hours of continuing education every year to retain their status. </span>
Aliun [14]3 years ago
3 0

The <em><u>correct answer</u></em> is:

The Rules of Practice under Circular 230.

Explanation:

An unenrolled return preparer is someone that is not an attorney, CPA, enrolled agent, enrolled retirement plan agent, or enrolled actuary, who prepares and signs a person's tax return as the paid preparer. They may also be someone who prepares a return but is not required to sign the return.

According to the IRS, unenrolled return preparers must comply with the rules of practice and conduct in order to exercise limited practice before the IRS.

There are two specific sets of rules that apply in Circular 230:

Duties and restrictions relating to practice (Subpart B of Cir. 230), and conduct considered to exhibit incompetence or disrepute (Subpart C, Section 10.51 of Cir. 230).

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An Egyptian merchant ship from 1500 BC was about 90 ft long and a Roman gallery
Verizon [17]

Answer:

Step-by-step explanation:

Its 0.38

7 0
3 years ago
Suppose Q and R are independent events. Find P(Q and R) if P(Q) = 0.63 and P(R) = 0.48.
Oksanka [162]
Hello,

Q and R are independent if p(Q and R)=p(Q)*p(R)
Here p(Q and R)=0.63-0.48=0.3024
ANSWER B
5 0
3 years ago
Read 2 more answers
In triangle RST, m∠R &gt; m∠S + m∠T. Which must be true of triangle RST? Check all that apply.
solmaris [256]

Answer:

1. m∠R > 90°

2. m∠S + m∠T < 90°

4. m∠R > m∠T

5. m∠R > m∠S

Step-by-step explanation:

<h3>General strategy</h3>
  1. prove the statement starting from known facts, or
  2. disprove the statement by finding a counterexample

Helpful fact:  Recall that the Triangle Sum Theorem states that m∠R + m∠S + m∠T = 180°.

<u>Option 1.  m∠R > 90°</u>

Start with m∠R > m∠S + m∠T.

Adding m∠R to both sides of the inequality...

m∠R + m∠R > m∠R + m∠S + m∠T

There are two things to note here:

  1. The left side of this inequality is 2*m∠R
  2. The right side of the inequality is exactly equal to the Triangle Sum Theorem expression

2* m∠R > 180°

Dividing both sides of the inequality by 2...

m∠R > 90°

So, the first option must be true.

<u>Option 2.  m∠S + m∠T < 90°</u>

Start with m∠R > m∠S + m∠T.

Adding (m∠S + m∠T) to both sides of the inequality...

m∠R + (m∠S + m∠T) >  m∠S + m∠T + (m∠S + m∠T)

There are two things to note here:

  1. The left side of this inequality is exactly equal to the Triangle Sum Theorem expression
  2. The right side of the inequality is 2*(m∠S+m∠T)

Substituting

180° > 2* (m∠S+m∠T)

Dividing both sides of the inequality by 2...

90° > m∠S+m∠T

So, the second option must be true.

<u>Option 3.  m∠S = m∠T</u>

Not necessarily.  While m∠S could equal m∠T, it doesn't have to.  

Example 1:  m∠S = m∠T = 10°;  By the triangle sum Theorem, m∠R = 160°, and the angles satisfy the original inequality.

Example 2:  m∠S = 15°, and m∠T = 10°;  By the triangle sum Theorem, m∠R = 155°, and the angles still satisfy the original inequality.

So, option 3 does NOT have to be true.

<u>Option 4.  m∠R > m∠T</u>

Start with the fact that ∠S is an angle of a triangle, so m∠S cannot be zero or negative, and thus m∠S > 0.

Add m∠T to both sides.

(m∠S) + m∠T > (0) + m∠T

m∠S + m∠T > m∠T

Recall that m∠R > m∠S + m∠T.

By the transitive property of inequalities, m∠R > m∠T.

So, option 4 must be true.

<u>Option 5.  m∠R > m∠S</u>

Start with the fact that ∠T is an angle of a triangle, so m∠T cannot be zero or negative, and thus m∠T > 0.

Add m∠S to both sides.

m∠S + (m∠T) > m∠S + (0)

m∠S + m∠T > m∠S

Recall that m∠R > m∠S + m∠T.

By the transitive property of inequalities, m∠R > m∠S.

So, option 5 must be true.

<u>Option 6.  m∠S > m∠T</u>

Not necessarily.  While m∠S could be greater than m∠T, it doesn't have to be.  (See examples 1 and 2 from option 3.)

So, option 6 does NOT have to be true.

4 0
1 year ago
Help i will give brainliest
Kamila [148]

Answer:

Step-by-step explanation:

Area of circle = 56 cm²

                   πr² = 56

                 3.14r² = 56

                         r²=56/3.14

                        r²= 17.83

                        r = √17.83

                        r = 4.22 cm

The diameter of the circle  = diagonal of the square

Diagonal of the square = 2 * 4.22 = 8.44 cm

x² + x² = 8.44²

2x² = 71.2336

  x² = 71.2336/2

  x² = 35.6168

x = 5.967 cm

5 0
3 years ago
Solve for the value of N N(4+6) = 11 + 29
Talja [164]
Use Math..way. Put in equation, hit solve, will give u val. for N
7 0
3 years ago
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