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3 years ago

How many toothpicks are used to create Figure 10? Describe how you found the answer.

Mathematics

1 answer:

finlep [7]3 years ago

5 0

So for the tenth figure you would have 58 toothpicks on the bottom layer and then because for all the layers above you wouldn't need a base, you would just find the number in the next row and from there keep subtracting 4:
58
35
31
27
23
19
15
11
7
3
Now add all these numbers and you should get a total of 229

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Which of the following relations is NOT a function?

Alexxandr [17]

Answer:

It is A.

Step-by-step explanation:

In function A we see that there are 2 ordered pairs with value 2 in the first position with y values 6 and 2. So this is not a function.

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3 years ago

How would you explain the proper use of distributive property ?

Maksim231197 [3]

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3 years ago

Best explained and correct answer gets brainliest.

Ahat [919]

The answer is C
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4 years ago

Read 2 more answers

Prove that: 5^31–5^29 is divisible by 100.

ANEK [815]

Answer:

See explanation

Step-by-step explanation:

Consider the expression

$5^{31}-5^{29}$

First, factor it:

$5^{31}-5^{29}=5^{29}\cdot(5^2-1)=5^{29}\cdot (25-1)=24\cdot 5^{29}$

Note that

$100=25\cdot 4$

Then

$5^{31}-5^{29}=24\cdot 5^{29}=6\cdot 4\cdot 25\cdot 5^{27}=6\cdot 100\cdot 5^{27}$

This shows that number 100 is a factor of the expression $5^{31}-5^{29}$ and, therefore, this expression is divisible by 100.

5 0

3 years ago

One of our brainliest, Konrad509, made this:

Reil [10]

$\dfrac{B_x \sqrt{74_x}}{1D_x}+J_x51_x=4G3_x$

A=10, B=11, C=12, etc.

$\dfrac{11\cdot x^0\cdot \sqrt{7\cdot x^1+4\cdot x^0}}{1\cdot x^1+13\cdot x^0}+19\cdot x^0\cdot (5\cdot x^1+1\cdot x^0)=4\cdot x^2+16\cdot x^1+3\cdot x^0\\\\\dfrac{11\sqrt{7x+4}}{x+13}+19(5x+1)=4x^2+16x+3\\\\\dfrac{11\sqrt{7x+4}}{x+13}+95x+19=4x^2+16x+3\\\\11\sqrt{7x+4}+95x(x+13)+19(x+13)=(4x^2+16x+3)(x+13)\\\\11\sqrt{7x+4}+95x^2+1235x+19x+247=4x^3+52x^2+16x^2+208x+3x+39\\\\11\sqrt{7x+4}=4x^3-27x^2-1043x-208\\\\121(7x+4)=(4x^3-27x^2-1043x-208)^2$

$121(7x+4)=(4x^3-27x^2-1043x-208)^2\\\\847x+484=16 x^6 - 216 x^5 - 7615 x^4 + 54658 x^3 + 1099081 x^2 + 433888 x + 43264\\\\16 x^6 - 216 x^5 - 7615 x^4 + 54658 x^3 + 1099081 x^2 + 433041 x +42780=0$

Now, the "only" thing that remains to do is solving the above equation.

While making this problem I only made sure it has a solution. I didn't try to solve it myself and I didn't know it will end up with such "convoluted" polynomial. Sorry to everyone who tried to solve it... m(_ _)m

I think the best way to approach it is using the rational root theorem since we know that $x\in\mathbb{N}$ . Moreover we can deduce that $x\geq19$ since there is $J$ and $J=19$ .

After you succesfully solve it, you should get the answer $x=20$ .

7 0

4 years ago