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goblinko [34]
3 years ago
14

A⁵÷a³ help ASAP need for maths HW arrrrrgggghhh

Mathematics
2 answers:
miv72 [106K]3 years ago
6 0

Answer:

a^{2}

Step-by-step explanation:

a^{5} /a^{3}

a^{5-3}

a^{2}

cestrela7 [59]3 years ago
5 0

Answer:

okay go ahead report me

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Please help me with this ​
prisoha [69]

Angle AOB + angle BOC = angle AOC

7x + 30 + 9x + 42 = 104

16x = 104 - 72

16x = 32

x = 2 degrees

Angle BOC = 9x + 42 = 18 + 42 = 60 degrees

3 0
2 years ago
Find the missing sides of the given similar triangle​
tiny-mole [99]
Provide an attachment so we can assist you.
4 0
3 years ago
In △BFD, m∠B = 34 ° and m∠FDC = 76°. What is m∠F and m∠FDB?
Paul [167]

Answer:

f=42

fdb=104

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
5.
Delicious77 [7]

You can solve for the velocity and position functions by integrating using the fundamental theorem of calculus:

<em>a(t)</em> = 40 ft/s²

<em>v(t)</em> = <em>v </em>(0) + ∫₀ᵗ <em>a(u)</em> d<em>u</em>

<em>v(t)</em> = -20 ft/s + ∫₀ᵗ (40 ft/s²) d<em>u</em>

<em>v(t)</em> = -20 ft/s + (40 ft/s²) <em>t</em>

<em />

<em>s(t)</em> = <em>s </em>(0) + ∫₀ᵗ <em>v(u)</em> d<em>u</em>

<em>s(t)</em> = 10 ft + ∫₀ᵗ (-20 ft/s + (40 ft/s²) <em>u</em> ) d<em>u</em>

<em>s(t)</em> = 10 ft + (-20 ft/s) <em>t</em> + 1/2 (40 ft/s²) <em>t</em> ²

<em>s(t)</em> = 10 ft - (20 ft/s) <em>t</em> + (20 ft/s²) <em>t</em> ²

6 0
2 years ago
the area of a trapezoid is 36 square inches. The height is 4 inches and one bases twice the length of the other base. What are t
vlada-n [284]
The formula for this is A= \frac{1}{2} ( b_{1} + b_{2} )h.  Filling in accordingly, 36= \frac{1}{2}(x+2x)(4).  This simplifies to 36= \frac{1}{2}(3x)(4) and 36=6x.  Therefore, x = 6 so the bases are 6 and 12.
8 0
2 years ago
Read 2 more answers
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